正则表达式在一行上找到 A 而不是 B [英] Regex to find A and not B on a line

问题描述

我正在寻找一个正则表达式来搜索我的 python 程序，以查找所有将 foo 而不是 bar 作为关键字参数传递给方法的行.我正在尝试前瞻和后视断言，但运气不佳.

I'm looking for a regex to search my python program to find all lines where foo, but not bar, is passed into a method as a keyword argument. I'm playing around with lookahead and lookbehind assertions, but not having much luck.

有什么帮助吗?

谢谢

推荐答案

如果您有一个字符串 foo 想要查找，另一个字符串 bar 不能是目前，你可以使用这个:

If you have a string foo that you want to find and another string bar that must not be present, you can use this:

^(?!.*bar).*foo

创建一个完全满足您所有要求的正则表达式非常困难，因为 Python 代码不是常规语言，但希望您应该能够使用它作为起点来获得足以满足您需求的东西.

Creating a regular expression that exactly meets all your requirements is very difficult as Python code is not a regular language, but hopefully you should be able to use this as a starting point to get something good enough for your needs.

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