'C'分段故障与二维数组 [英] 'C' Segmentation fault with 2d array

问题描述

有人能解释我为什么这个code不起作用？

Can anybody explain me why this code doesn't work?

#include <stdio.h>
#include <stdlib.h>

void findAndPrint(char *arr[], int year, int month, int day);

int main()
{
    char *dayTab[] = {
        {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31},
        {31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}
    };
    findAndPrint(dayTab, 3, 3, 3);
    getchar();
    return 0;
}

void findAndPrint(char *arr[], int year, int month, int day ){
    int d = 0;
    if(month > 12 || month < 1 || day > 31 || day<1)
        return;
    int leap = ((year%4==0 && year%100!=0) || year%400 == 0)?1:0;
    int i;
    for(i=0; i<month-1; i++){
        d += arr[leap][i];
    }
    d+= day;
    printf("Day = %d", d);
}

IDE（code ::块）写道：计划接收信号SIGSEGV，分割过错。

IDE(Code::Blocks) writes "Program received signal SIGSEGV. Segmentation fault."

推荐答案

首先，你需要字符的二维数组，的不的指针数组为字符。

First you need a 2d array of characters, not an array of pointers to characters.

char dayTab[][12] = {
    {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31},
    {31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}
};

然后，你必须改变函数接受该类型。

Then you have to change the function to accept that type.

void findAndPrint(char arr[][12], int year, int month, int day ) ;

其余看起来不错。

The rest looks ok.

与参数尝试：

findAndPrint(dayTab, 2014, 10, 12);

让我们的一天： 285

这是正确的，yaaay！

Which is correct, yaaay!

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