二维数组的分段错误 [英] segmentation fault for 2D arrays

问题描述

我想定义一个非常大的二维数组.但它给了我分段错误?

I want to define a 2D array of very big size. But it is giving me segmentation fault?

  #include <stdio.h>

  int main () {
       int i;
       int temp[4000][5000];
      for (i = 0; i < 5; i++)
      {
          printf ("Hello World\n");
      }
  }

有人可以建议我其他方式吗?内存初始化有问题吗?提前致谢

Can anyone please suggest me some other way? Is there some problem with memory initialization? Thanks in advance

推荐答案

你可以只在一个数组中分配整个表，但你将无法使用两个方括号访问带有索引的数组数据:

You can allocate the whole table in only one array but you won't be able to access array data with indices using two square brackets:

int * temp = malloc(4000*5000*sizeof(int));

要访问之前编写 temp[i][j] 的元素 (i,j)，现在应该按以下方式计算索引:

to access the element (i,j) where previously you wrote temp[i][j], now you should now compute the index the following way:

temp[i*5000+j];

并且不要忘记之后释放为您的表分配的内存:

and do not forget to free the memory allocated for your table afterward:

free(temp);

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