C：在常量数组的维数报告错误 [英] c: const in the dimension of arrays reports errors

问题描述

#include <stdio.h>
#include <stdlib.h>

const int N = 5;

int main()
{
    int vett[N] = {1, 2, 3, 4, 5};
    return 0;
}

什么是code，这部分的问题？编译器报告我这些错误和警告：

What is the problem in this part of code? the compiler report me these error and warnings:

error: variable-sized object may not be initialized
warning: excess elements in array initializer [enabled by default]
warning: (near initialization for 'vett') [enabled by default]

我知道我可以使用定义指令来解决，但我以前在C ++编程，我不想使用改变我的老习惯常量。也有一些是我能做什么？谢谢你。

I know I can use the define directive to solve but I used to program in c++ and I don't want to change my old habits using const. There is something I can do? Thanks.

推荐答案

和C ++不同，甚至与 const int的N = 5 ， N 不视为C.因此，一个恒定的前pression INT vett [N] 是不是一个正常的（定长）阵列，这是一个可变长度的数组。

Unlike C++, even with const int N = 5, N is not considered as a constant expression in C. So int vett[N] is not a normal (fixed length) array, it's a variable length array.

在这种情况下，你还是应该使用：

In this case, you should still use:

#define N 5

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