Python Code-While 循环永无止境 [英] Python Code-While loop never end

问题描述

我是 Python 新手.正在尝试学习它.这是我的代码:

I am new to Python.Trying to learn it. This is my Code:

import sys
my_int=raw_input("How many integers?")
try:
    my_int=int(my_int)
except ValueError:
    ("You must enter an integer")
ints=list()
count=0
while count<my_int:
    new_int=raw_input("Please enter integer{0}:".format(count+1))
    isint=False
    try:
        new_int=int(new_int)
    except:
        print("You must enter an integer")
    if isint==True:
        ints.append(new_int)
        count+=1

代码正在执行但循环总是重复并且不允许我输入第二个整数.

The code is executing but the loop is always repeating and is not allowing me to enter 2nd integer.

输出:

How many integers?3
Please enter integer1:1
Please enter integer1:2
Please enter integer1:3
Please enter integer1:

我能知道我的代码有什么问题吗?谢谢

Can i know what is wrong with my code? Thank you

推荐答案

你的代码的问题是 isint 永远不会改变并且总是 False，因此 count 永远不会改变.我猜你的意图是当输入是一个有效的整数时，增加 count；否则，对 count 不做任何事情.

The problem of your code is that isint is never changed and is always False, thus count is never changed. I guess your intention is that when the input is a valid integer, increase the count;otherwise, do nothing to count.

这里是代码，不需要isint标志:

Here is the code, isint flag is not need:

import sys

while True:
    my_int=raw_input("How many integers?")
    try:
        my_int=int(my_int)
        break
    except ValueError:
        print("You must enter an integer")
ints=list()
count=0
while count<my_int:
    new_int=raw_input("Please enter integer{0}:".format(count+1))
    try:
        new_int=int(new_int)
        ints.append(new_int)
        count += 1
    except:
        print("You must enter an integer")

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