如何使用 XSLT 更新 XML 中的单个值? [英] How to use XSLT to update a single value in an XML?

问题描述

我有一个巨大的 XML 文件，我想在其中更新单个值.有没有办法编写一个 XSLT 文件，它可以通过简单的更改生成现有 XML 文件的精确副本?

I have a giant XML file in which I would like to update a single value. Is there a way to write an XSLT file which will produce an exact copy of the existing XML file with a simple change?

例如，假设我有以下 XML，并且我想将员工 Martin 的职位编号更改为 100.我该怎么做?

For instance, let's say I have the following XML and that I want to change the position number of employee Martin to 100. How can I do this?

<?xml version="1.0" encoding="utf-8"?>
<Employees>
  <!-- ... -->

  <Employee name="Martin">
    <Position number="50" />
  </Employee>

    <!-- ... -->
</Employees>

推荐答案

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    version="1.0">

    <!--Identity template that will copy every
        attribute, element, comment, and processing instruction
        to the output-->
    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>

    <!--more specific template match on @number that will 
        change the value to 100-->
    <xsl:template match="Employee[@name='Martin']/Position/@number">
        <xsl:attribute name="number">100</xsl:attribute>
    </xsl:template>

</xsl:stylesheet>

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