根据 NodeJS 中的模式 (xsd) 验证 XML [英] Validating XML against a schema (xsd) in NodeJS

问题描述

NPM 中的任何 XML 库是否支持针对 XSD 架构验证 XML?

Do any of the XML libraries in NPM support the validation of XML against an XSD schema?

我会看自己，但是:

$ npm search xml 2>/dev/null | wc -l
212

注意:xsd 包不是看起来的那样，node-xerces 已损坏/为空.

Note: the xsd package is not what it seems and node-xerces is broken/empty.

推荐答案

Hij1nx (Paolo Fragomeni) 将我指向 https://github.com/polotek/libxmljs

Hij1nx (Paolo Fragomeni) pointed me at https://github.com/polotek/libxmljs

在试图弄清楚 API 半小时后，我有了一个解决方案:

After half an hour of trying to figure out the API, I have a solution:

#!/usr/local/bin/node
var x = require('libxmljs');

var xsd = '<?xml version="1.0" encoding="utf-8" ?><xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns="http://example.com/XMLSchema/1.0" targetNamespace="http://example.com/XMLSchema/1.0" elementFormDefault="qualified" attributeFormDefault="unqualified"><xs:element name="foo"></xs:element></xs:schema>'
var xsdDoc = x.parseXmlString(xsd);

var xml0 = '<?xml version="1.0" encoding="UTF-8"?><foo xmlns="http://example.com/XMLSchema/1.0"></foo>';
var xmlDoc0 = x.parseXmlString(xml0);
var xml1 = '<?xml version="1.0" encoding="UTF-8"?><bar xmlns="http://example.com/XMLSchema/1.0"></bar>';
var xmlDoc1 = x.parseXmlString(xml1);

var result0 = xmlDoc0.validate(xsdDoc);
console.log("result0:", result0);

var result1 = xmlDoc1.validate(xsdDoc);
console.log("result1:", result1);

这会产生输出:

result0: true
result1: false

我不知道这是否/如何与通过 URI 引用其他模式的模式一起工作.

I have no idea whether/how this will work with schemas which reference other schemas via URIs.

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