获取 UndeclaredThrowableException 而不是我自己的异常 [英] Getting UndeclaredThrowableException instead of my own exception

问题描述

我有以下代码

public Object handlePermission(ProceedingJoinPoint joinPoint, RequirePermission permission) throws AccessException, Throwable {
    System.out.println("Permission = " + permission.value());
    if (user.hasPermission(permission.value())) {
        System.out.println("Permission granted ");
        return joinPoint.proceed();
    } else {
        System.out.println("No Permission");
        throw new AccessException("Current user does not have required permission");
    }

}

当我使用没有权限的用户时，我得到 java.lang.reflect.UndeclaredThrowableException 而不是 AccessException.

When I use a user that does not have permissions, I get java.lang.reflect.UndeclaredThrowableException instead of AccessException.

推荐答案

AccessException 是一个已检查的异常，但它是从没有在其 throws<中声明它的方法抛出的/code> 子句(实际上 - 从拦截该方法的方面来看).这是 Java 中的异常情况，因此您的异常被包裹在 UndeclaredThrowableException 中，这是未经检查的.

AccessException is a checked exception, but it was thrown from the method that doesn't declare it in its throws clause (actually - from the aspect intercepting that method). It's an abnormal condition in Java, so your exception is wrapped with UndeclaredThrowableException, which is unchecked.

要按原样获取异常，您可以在切面拦截的方法的 throws 子句中声明它，或者使用另一个未经检查的异常(即 RuntimeException) 而不是 AccessException.

To get your exception as is, you can either declare it in the throws clause of the method being intercepted by your aspect, or use another unchecked exception (i.e. a subclass of RuntimeException) instead of AccessException.

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