如何处理 Actionscript 中的数字精度? [英] How to deal with Number precision in Actionscript?

问题描述

我已使用 BlazeDS 将 BigDecimal 对象序列化为 Actionscript.一旦它们将 Actionscript 作为 Number 对象命中，它们就会具有如下值:

I have BigDecimal objects serialized with BlazeDS to Actionscript. Once they hit Actionscript as Number objects, they have values like:

140475.32 变成 140475.31999999999998

我该如何处理?问题是，如果我使用 NumberFormatter 的精度为 2，则该值将被截断为 140475.31.有什么想法吗?

How do I deal with this? The problem is that if I use a NumberFormatter with precision of 2, then the value is truncated to 140475.31. Any ideas?

推荐答案

这是我针对该问题的通用解决方案(我有 在此处写了博客):

This is my generic solution for the problem (I have blogged about this here):

var toFixed:Function = function(number:Number, factor:int) {
  return Math.round(number * factor)/factor;
}

例如:

trace(toFixed(0.12345678, 10)); //0.1

• 将0.12345678乘以10；这给了我们 1.2345678.
• 当我们取整 1.2345678 时，我们得到 1.0，
• 最后，1.0 除以 10 等于 0.1.
• Multiply 0.12345678 by 10; that gives us 1.2345678.
• When we round 1.2345678, we get 1.0,
• and finally, 1.0 divided by 10 equals 0.1.

另一个例子:

trace(toFixed(1.7302394309234435, 10000)); //1.7302

• 将1.7302394309234435乘以10000；这给了我们 17302.394309234435.
• 当我们舍入 17302.394309234435 时，我们得到 17302，
• 最后，17302 除以 10000 等于 1.7302.
• Multiply 1.7302394309234435 by 10000; that gives us 17302.394309234435.
• When we round 17302.394309234435 we get 17302,
• and finally, 17302 divided by 10000 equals 1.7302.

<小时>编辑

基于匿名答案下面，对方法上的参数进行了很好的简化，使精度大大提高更直观.例如:

Based on the anonymous answer below, there is a nice simplification for the parameter on the method that makes the precision much more intuitive. e.g:

var setPrecision:Function = function(number:Number, precision:int) {
 precision = Math.pow(10, precision);
 return Math.round(number * precision)/precision;
}

var number:Number = 10.98813311;
trace(setPrecision(number,1)); //Result is 10.9
trace(setPrecision(number,2)); //Result is 10.98
trace(setPrecision(number,3)); //Result is 10.988 and so on

注意我在此处添加了此内容，以防万一有人将其视为答案并且不向下滚动...

N.B. I added this here just in case anyone sees this as the answer and doesn't scroll down...

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