为什么List<String>中只有一个数据? [英] Why there is only one data in the List&lt;String&gt;?

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本文介绍了为什么List<String>中只有一个数据?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我使用游标进行数据库选择,并希望将所有数据放在一个列表中,然后返回到主活动.但是经过调试,发现返回值里面只有第一个数据.

I used cursor for database selecting and want to put all the data inside a List, then return to the mainactivity. But after debugging, I found that there is only the first data inside the return value.

public List<String> select1 (String ReservedState, String mycity, String mystreet, String mypostcode){
    ReservedState="Free";
    SQLiteDatabase Database1=dbHelper1.getWritableDatabase();
    String[] columns={DbHelper1.KEY_ID1,DbHelper1.KEY_RESERVEDSTATE, DbHelper1.KEY_GEOGRAPHICALLOCATION,DbHelper1.KEY_CITY,DbHelper1.KEY_POSTCODE,DbHelper1.KEY_STREET};
    Cursor cursor=Database1.query(DbHelper1.TABLE_NAME_1,columns, DbHelper1.KEY_RESERVEDSTATE+"='"+ReservedState+"' AND "+DbHelper1.KEY_CITY+"='"+mycity+"' AND "+DbHelper1.KEY_POSTCODE+"='"+mypostcode+"' AND "+DbHelper1.KEY_STREET+"='"+mystreet+"'",null,null,null,null);
    //StringBuffer buffer=new StringBuffer();
    List<String> al=new ArrayList<String>();
    cursor.moveToFirst();
    while(!cursor.isAfterLast()){
        int index1=cursor.getColumnIndex(DbHelper1.KEY_ID1);
        String id=cursor.getString(index1);
        al.add(id);
        cursor.moveToNext();
    }
    return al;

}

推荐答案

public List<String> select1 (String ReservedState, String mycity, String mystreet, String mypostcode){
        ReservedState="Free";
        SQLiteDatabase Database1=dbHelper1.getWritableDatabase();
        String[] columns={DbHelper1.KEY_ID1,DbHelper1.KEY_RESERVEDSTATE, DbHelper1.KEY_GEOGRAPHICALLOCATION,DbHelper1.KEY_CITY,DbHelper1.KEY_POSTCODE,DbHelper1.KEY_STREET};
        Cursor cursor=Database1.query(DbHelper1.TABLE_NAME_1,columns, DbHelper1.KEY_RESERVEDSTATE+"='"+ReservedState+"' AND "+DbHelper1.KEY_CITY+"='"+mycity+"' AND "+DbHelper1.KEY_POSTCODE+"='"+mypostcode+"' AND "+DbHelper1.KEY_STREET+"='"+mystreet+"'",null,null,null,null);
        Log.e("Cursor",""+cursor.getCount());
        //StringBuffer buffer=new StringBuffer();
        List<String> list=new ArrayList<String>();
        do{
            int index1=cursor.getColumnIndex(DbHelper1.KEY_ID1);
            String id=cursor.getString(index1);
            list.add(id);
          }while(cursor.moveToNext());
        return al;
    }

试试这个.希望这会有所帮助.

Try this. Hope this will help.

这篇关于为什么List<String>中只有一个数据?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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