将整数转换为数组 [英] convert an integer number into an array

问题描述

我正在尝试将 C 中的整数转换为包含该数字的每个数字的数组

I am trying to convert an integer number in C into an array containing each of that number's digits

即如果我有

int number = 5400

我怎么去

int numberArray[4]

哪里

numberArray[0] = 0;
numberArray[1] = 0;
numberArray[2] = 4;
numberArray[3] = 5;

感谢收到任何建议.

推荐答案

这适用于数字 >= 0

This would work for numbers >= 0

#include <math.h>

char * convertNumberIntoArray(unsigned int number) {
    int length = (int)floor(log10((float)number)) + 1;
    char * arr = new char[length];
    int i = 0;
    do {
        arr[i] = number % 10;
        number /= 10;
        i++;
    } while (number != 0);
    return arr;
}

只是多一点 C 风格，但更神秘.

Just a little bit more C style but more cryptic.

#include <math.h>

char * convertNumberIntoArray(unsigned int number) {
    unsigned int length = (int)(log10((float)number)) + 1;
    char * arr = (char *) malloc(length * sizeof(char)), * curr = arr;
    do {
        *curr++ = number % 10;
        number /= 10;
    } while (number != 0);
    return arr;
}

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