将char数组转换为整数 [英] converting char array to integer
问题描述
你能帮我把一个char数组转换成一个整数。我正在尝试的东西
喜欢..
char carray [5];
int numb;
carray [0] = 1;
carray [1] = 5;
carray [2] = 1;
carray [3] = 5;
numb =（int）carray; //这就是我要转换的内容
我知道这不起作用。你有没有人建议转换
。这将在16位μc中实现。有没有使用sprintf或乘法之类的解决方案
。
提前谢谢
Densil
Hi,
Can you help me conver a char array into an integer. I am trying something
like..
char carray[5];
int numb;
carray[0] = 1;
carray[1] = 5;
carray[2] = 1;
carray[3] = 5;
numb = (int) carray; // this is what I want to convert
I know this doesnt work. Does anyone of you have a suggestion for that
conversion. This is to be implemented in a 16bit μc. Is there a solution
without using anything like sprintf or multiplication.
Thanks in advance
Densil
推荐答案
2004年4月15日星期四05:26:27 -0400，silentlights写道：
On Thu, 15 Apr 2004 05:26:27 -0400, silentlights wrote:
你能帮我把char数组转换成整数吗？我正在尝试一些
喜欢..
char carray [5];
int numb;
carray [0] = 1;
carray [1] = 5;
carray [2] = 1;
carray [3] = 5;
numb =（int）carray; //这就是我要转换的内容
我知道这不起作用。你有没有人建议进行转换。这将在16位μc中实现。是否有解决方案
没有使用sprintf或乘法之类的东西。
Hi,
Can you help me conver a char array into an integer. I am trying something
like..
char carray[5];
int numb;
carray[0] = 1;
carray[1] = 5;
carray[2] = 1;
carray[3] = 5;
numb = (int) carray; // this is what I want to convert
I know this doesnt work. Does anyone of you have a suggestion for that
conversion. This is to be implemented in a 16bit μc. Is there a solution
without using anything like sprintf or multiplication.
转换后你想要什么''麻木'？
1515？
5151？
12？
其他东西
< br $>
-
NPV
大字印刷品，小字体带走
Tom Waits - 向上走吧
What would you want ''numb'' to be after the conversion?
1515 ?
5151 ?
12 ?
Something else
--
NPV
"the large print giveth, and the small print taketh away"
Tom Waits - Step right up
" silentlights" < SI ********** @ yahoo.co.uk>在消息中写道
news：89 ****************************** @ localhost.ta lkaboutprogramming。 com ...
"silentlights" <si**********@yahoo.co.uk> wrote in message
news:89******************************@localhost.ta lkaboutprogramming.com...
你能帮我把一个char数组转换成一个整数。我正在尝试一些
喜欢..
char carray [5];
int numb;
carray [0] = 1;
carray [1] = 5;
carray [2] = 1;
carray [3] = 5;
numb =（int）carray; //这就是我要转换的内容
我知道这不起作用。你有没有人建议进行转换。这将在16位c中实现。有没有使用sprintf或乘法之类的解决方案。
Can you help me conver a char array into an integer. I am trying something
like..
char carray[5];
int numb;
carray[0] = 1;
carray[1] = 5;
carray[2] = 1;
carray[3] = 5;
numb = (int) carray; // this is what I want to convert
I know this doesnt work. Does anyone of you have a suggestion for that
conversion. This is to be implemented in a 16bit c. Is there a solution
without using anything like sprintf or multiplication.
#include< stdlib.h>
char carray [5];
int numb;
....
carray [0] =''1''; // 1！=''1''
carray [1] ='''5'';
carray [2] =''1'';
carray [3] ='''5'';
carray [4] = 0; // null终止字符串
numb = atoi（carray）;
....
-
Stephen Sprunk愚蠢的人用智能环绕自己
CCIE＃3723人。聪明的人围绕着他们自己与他们不同意的K5SSS聪明人。 --Aaron Sorkin
#include <stdlib.h>
char carray[5];
int numb;
....
carray[0] = ''1''; // 1 != ''1''
carray[1] = ''5'';
carray[2] = ''1'';
carray[3] = ''5'';
carray[4] = 0; // null termination of string
numb = atoi(carray);
....
--
Stephen Sprunk "Stupid people surround themselves with smart
CCIE #3723 people. Smart people surround themselves with
K5SSS smart people who disagree with them." --Aaron Sorkin
silentlights写道：
silentlights wrote:
char carray [5];
int numb;
carray [0] = 1;
carray [1] = 5;
carray [2] = 1;
carray [3] = 5;
numb =（int）carray; //这就是我要转换的内容
char carray[5];
int numb;
carray[0] = 1;
carray[1] = 5;
carray[2] = 1;
carray[3] = 5;
numb = (int) carray; // this is what I want to convert
您还可以做什么（但这只适用于32位微处理器）
carray [0] = 1;
carray [1] = 5;
carray [2] = 1;
carray [3 ] = 5;
numb =（int *）carray; // carray是一个char *已经把它变成了一个int
*
至于你提到的情况，如果int''是16位而char'是8
位这只会将数字设置为15或51，具体取决于你正在使用的机器的b / b
的字节顺序。
Ahmed
What you could also do (but this will only work on 32-bit micro-processors)
carray[0] = 1;
carray[1] = 5;
carray[2] = 1;
carray[3] = 5;
numb = (int *) carray; // carray is a char* already so cast it into an int
*
As for the case you''re mentioning, if int''s are 16 bits and char''s are 8
bits this will only set num to either 15 or 51 depending on the endianity of
the machine you''re using.
Ahmed
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