将 NSString 转换为 char 数组 [英] Convert NSString into char array

问题描述

我有一个 char[] 类型的变量，我想在其中复制 NSString 值.如何将 NSString 转换为 char 数组?

I have a variable of type char[] and I want to copy NSString value in it. How can I convert an NSString to a char array?

推荐答案

使用-[NSString UTF8String]:

NSString *s = @"Some string";
const char *c = [s UTF8String];

您也可以使用 -[NSString cStringUsingEncoding:] 如果你的字符串是用非 UTF-8 编码的.

You could also use -[NSString cStringUsingEncoding:] if your string is encoded with something other than UTF-8.

一旦你有了 const char *，你就可以像使用 chars 数组一样使用它:

Once you have the const char *, you can work with it similarly to an array of chars:

printf("%c
", c[5]);

如果要修改字符串，请复制:

If you want to modify the string, make a copy:

char *cpy = calloc([s length]+1, 1);
strncpy(cpy, c, [s length]);
// Do stuff with cpy
free(cpy);

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