当另一个正在运行时，如何暂停一个倒计时? [英] How can I pause one CountDown Timer when another one is running?
问题描述
我的程序中有两个 CountDownTimer:一个 4 秒一个，一个 24 秒一个.我希望较长的计时器每 4 秒暂停一次，较短的计时器正在运行.然后当短定时器结束时，长定时器开始倒计时.这是两个计时器的代码:
I have two CountDownTimers in my program: a 4 second one, and 24 second one. I want the longer timer to be paused for every 4 seconds the shorter timer is running. Then when the short timer finishes, the long timer begins counting down. Here's the code for the two timers:
final CountDownTimer loop = new CountDownTimer(4000, 1000) {
@Override
public void onTick(long millisUntilFinished) {
}
@Override
public void onFinish() {
number.setVisibility(View.GONE);
final TextView prompt = (TextView) findViewById(R.id.prompt);
prompt.setVisibility(View.VISIBLE);
prompt.setText(" Enter the number");
final EditText input = (EditText) findViewById(R.id.enterAnswer);
input.setVisibility(View.VISIBLE);
input.setOnKeyListener(new View.OnKeyListener() {
@Override
public boolean onKey(View v, int keyCode, KeyEvent event) {
if (event.getAction() == KeyEvent.ACTION_DOWN) {
switch (keyCode) {
case KeyEvent.KEYCODE_ENTER:
Editable answer = input.getText();
int finalAnswer = Integer.parseInt(String.valueOf(answer));
int finalLoadG1 = Integer.parseInt(String.valueOf(number.getText()));
input.setVisibility(View.GONE);
prompt.setVisibility(View.GONE);
if (finalAnswer == finalLoadG1) {
score++;
}
number.setVisibility(View.VISIBLE);
int loadG1 = generateG1.nextInt(1000000)+10000;
number.setText(""+loadG1);
input.getText().clear();
start();
return true;
default:
}
}
return false;
}
});
}
}.start();
new CountDownTimer(24000, 1000) {
@Override
public void onTick (long millisUntilFinished) {
}
@Override
public void onFinish() {
TextView result = (TextView) findViewById(R.id.outcome);
result.setText("Score: "+ score);
TextView prompt = (TextView) findViewById(R.id.prompt);
prompt.setVisibility(View.GONE);
final EditText input = (EditText) findViewById(R.id.enterAnswer);
input.setVisibility(View.GONE);
loop.cancel();
number.setVisibility(View.GONE);
}
}.start();
我想过命名较长的计时器，然后将 name.pause() 放在 onTick 中以表示较短的计时器.问题是，由于较长的计时器写在较短的计时器之后，因此在初始化之前无法识别它的名称.Java按顺序读取东西，对吧?或者是所有语言?
I thought about naming the longer timer, then putting name.pause() in the onTick for the shorter timer. Issue is, because the longer timer is written after the shorter one, it's name is not recognizable before it has been initialized. Java reads things in order, right? Or is that all languages?
如果有人能帮助我，我将不胜感激.
If anyone could help me out here, I'd be grateful.
作为任何人都可以回答的附带问题，当用户在 EditText(用于 int)上按下 Enter 以不提交任何内容时，是否有任何方法可以防止应用程序崩溃?比如，我可以让应用继续运行而不强制停止吗?
As a side question for anyone able to answer, is there any way to prevent an app from crashing when a user presses enter on an EditText (meant for an int) to submit nothing? Like, can I just have the app continue without force stopping?
非常感谢.
推荐答案
在代码中创建单独的方法来启动/暂停/恢复 24 秒计时器.您需要存储您的 MilliTillFinished 24 秒计时器，以便您可以将其传递给恢复计时器方法.您可以在 4 秒计时器的 onTick() 方法上暂停 24 秒计时器，然后在 onFinish() 方法上恢复.
Create separate methods to start/pause/resume 24 second timer in your code. You need to store Your milliTillFinished of 24 seconds timer so you can pass it to resume timer method. You can pause 24 second timer on onTick() method of 4 second timer and resume it on onFinish() method.
启动计时器:
public void timerStart(long timeLengthMilli) {
timer = new CountDownTimer(timeLengthMilli, 1000) {
@Override
public void onTick(long milliTillFinish) {
milliLeft=milliTillFinish;
}
暂停计时器:
public void timerPause() {
timer.cancel();
}
要恢复计时器:
private void timerResume() {
timerStart(milliLeft);
}
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