java Arrays.sort 二维数组 [英] java Arrays.sort 2d array

问题描述

我希望根据 [][0] 的值对以下数组进行排序

I am looking to sort the following array based on the values of [][0]

double[][] myArr = new double[mySize][2];

例如，myArr 的内容是:

so for example, myArr contents is:

1      5
13     1.55
12     100.6
12.1   .85

我希望它到达:

1      5
12     100.6
12.1   .85
13     1.55

我希望无需实现我自己的排序即可做到这一点.

I am looking to do this without having to implement my own sort.

推荐答案

Use Overloaded Arrays#Sort(T[] a, Comparator c) 将 Comparator 作为第二个参数.

Use Overloaded Arrays#Sort(T[] a, Comparator c) which takes Comparator as the second argument.

double[][] array= {
{1, 5},
{13, 1.55},
{12, 100.6},
{12.1, .85} };

java.util.Arrays.sort(array, new java.util.Comparator<double[]>() {
    public int compare(double[] a, double[] b) {
        return Double.compare(a[0], b[0]);
    }
});

JAVA-8:代替那个大的比较器，我们可以使用如下的 lambda 函数 -

JAVA-8: Instead of that big comparator, we can use lambda function as following-

Arrays.sort(array, Comparator.comparingDouble(o -> o[0]));

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