如何使用Arrays.sort（）按长度排序String数组 [英] How to sort String array by length using Arrays.sort()

问题描述

我正在尝试使用 Arrays.sort（）根据长度对字符串数组进行排序，但是这会按字典顺序而不是按长度对字符串进行排序。这是我的代码：

I am trying to sort an array of strings according to their length using Arrays.sort(), but this sorts the strings lexicographically rather than by length. Here is my code:

S = "No one could disentangle correctly"
String W[] = S.split(" ");
Arrays.sort(W);

排序后：

correctly
could
disentangle
no
one

但我想要的是

no  //length = 2
one //length = 3
could //length = 4 and likewise
correctly
disentangle

如何获得上述输出？请给出JDK 1.7&的回答。 JDK1.8。

How can I get the above output? Please give answer for JDK 1.7 & JDK1.8.

推荐答案

如果您使用 JDK 1.8或更高版本，那么您可以使用 lambda表达式，如 matt 回答。但是，如果您使用 JDK 1.7或更早版本，请尝试编写自定义Comparator ，如下所示：

If you are using JDK 1.8 or above then you could use lambda expression like matt answer. But if you are using JDK 1.7 or earlier version try to write a custom Comparator like this:

String S = "No one could disentangle correctly";
String W[] = S.split(" ");
Arrays.sort(W, new java.util.Comparator<String>() {
    @Override
    public int compare(String s1, String s2) {
        // TODO: Argument validation (nullity, length)
        return s1.length() - s2.length();// comparision
    }
});

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