C＃：输入流是不是一个有效的二进制格式 [英] C#: The input stream is not a valid binary format

问题描述

我有一个问题，在C＃/ ASP.NET，这给确切的错误反序列化：

I have a problem with deserializing in C#/ASP.NET, which gives the exact error:

输入流不是有效的二进制格式。起始内容（以字节为单位）有：41-41-45-41-41-41-44-2F-2F-2F-2F-2F-41-51-41-41-41 ... 的

我所试图做的

我有3班的结构。我有一个A类是一个基类，然后B类和C这是从的。

I have a structure with 3 classes. I have a class A which is a base class, and then class B and C which are derived from A.

我想随机存储B型和C在使用LINQ to SQL数据库，与类型VARCHAR（MAX）列。
作为长度约为15.000我不能使用二进制。

I am trying to store random types of B and C in the database using LINQ to SQL, in a column with the type VARCHAR(MAX). I cannot use BINARY as the length is around 15.000.

我的code ...

错误是在最后$ C $使用cblock

Error is in the LAST codeblock

的商务C＃code的第一层存储记录的

    private void AddTraceToDatabase(FightTrace trace)
    {
        MemoryStream recieverStream = new MemoryStream();
        MemoryStream firedStream = new MemoryStream();
        MemoryStream moveStream = new MemoryStream();

        BinaryFormatter binaryFormatter = new BinaryFormatter();
        binaryFormatter.Serialize(recieverStream,trace.Reciever);
        binaryFormatter.Serialize(firedStream,trace.FiredBy);
        binaryFormatter.Serialize(moveStream,trace.Move);

        string reciever = Convert.ToBase64String(recieverStream.ToArray());
        string fired = Convert.ToBase64String(firedStream.ToArray());
        string move = Convert.ToBase64String(moveStream.ToArray());


        this.dataAccess.AddFightTrace(trace.TraceType.ToString(),reciever,move,fired,trace.DateTime,this.FightId);
    }

的 C＃code在数据访问层 - 存储记录的

    public void AddFightTrace(string type, string reciever, string Move, string firedBy, DateTime firedAt, int fightid)
    {
        GameDataContext db = new GameDataContext();
        dbFightTrace trace = new dbFightTrace();
        trace.TraceType = type;

        trace.Reciever = reciever;
        trace.Move = Move;
        trace.FiredBy = firedBy;
        trace.FiredAt = firedAt;
        trace.FightId = fightid;

        db.dbFightTraces.InsertOnSubmit(trace);
        db.SubmitChanges();
    }

的 C＃code获得在数据库中的条目的

    public List<dbFightTrace> GetNewTraces(int fightid, DateTime lastUpdate)
    {
        GameDataContext db = new GameDataContext();
        var data = from d in db.dbFightTraces
                   where d.FightId==fightid && d.FiredAt > lastUpdate
                   select d;

        return data.ToList();
    }

的 C＃工厂，从LINQ转换为SQL类我的对象的

这是这里的错误出现。

    public FightTrace CreateTrace(dbFightTrace trace)
    {
        TraceType traceType = (TraceType) Enum.Parse(typeof(TraceType), trace.TraceType);
        BinaryFormatter formatter = new BinaryFormatter();

        System.Text.UTF8Encoding enc = new System.Text.UTF8Encoding();

        MemoryStream recieverStream = new MemoryStream(enc.GetBytes(trace.Reciever));
        recieverStream.Position = 0;
        MemoryStream firedStream = new MemoryStream(enc.GetBytes(trace.FiredBy));
        firedStream.Position = 0;
        MemoryStream movedStream = new MemoryStream(enc.GetBytes(trace.Move));
        movedStream.Position = 0;

        // THE NEXT LINE HERE CAUSES THE ERROR
        NPC reciever = formatter.Deserialize(recieverStream) as NPC;
        Player fired = formatter.Deserialize(firedStream) as Player;
        BaseAttack attack = formatter.Deserialize(movedStream) as BaseAttack;

        FightTrace t = new FightTrace(traceType,reciever,attack,fired);
        t.TraceId = trace.FightTraceId;
        t.DateTime = trace.FiredAt;
        return t;
    }

因此​​，当第一Deserialize方法运行时，与上述错误的错误happends

So the error happends when the first Deserialize method is run, with the above error.

我已经试过几件事，但我完全迷失在这一个。

I have tried several things but I am quite lost on this one..

谢谢！ ： - ）

推荐答案

我觉得从丁文的base64为字节后面是错误的。

I think the coversion back from base64 to bytes is wrong.

试试这个：

var bytes = Convert.FromBase64String(base64);

=>

 MemoryStream recieverStream = new MemoryStream(Convert.FromBase64String(trace.Reciever));

  NPC reciever = formatter.Deserialize(recieverStream) as NPC;

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