你如何选择“x"?Python中列表中唯一数字的数量? [英] How do you pick "x" number of unique numbers from a list in Python?

问题描述

我需要从列表中挑选出x"个非重复的随机数.例如:

all_data = [1, 2, 2, 3, 4, 5, 6, 7, 8, 8, 9, 10, 11, 11, 12, 13, 14, 15, 15]

如何选择像 [2, 11, 15] 而不是 [3, 8, 8] 这样的列表?

解决方案

这正是 random.sample() 确实如此.

<预><代码>>>>随机样本(范围(1、16)、3)[11, 10, 2]

编辑:我几乎可以肯定这不是您所要求的，但我被迫包含此评论:如果您想从中抽取样本的总体包含重复项，则必须将其删除第一:

population = [1, 2, 3, 4, 5, 6, 5, 4, 3, 2, 1]人口 = 集合(人口)样本 = random.sample(人口，3)

I need to pick out "x" number of non-repeating, random numbers out of a list. For example:

all_data = [1, 2, 2, 3, 4, 5, 6, 7, 8, 8, 9, 10, 11, 11, 12, 13, 14, 15, 15]

How do I pick out a list like [2, 11, 15] and not [3, 8, 8]?

解决方案

That's exactly what random.sample() does.

>>> random.sample(range(1, 16), 3)
[11, 10, 2]

Edit: I'm almost certain this is not what you asked, but I was pushed to include this comment: If the population you want to take samples from contains duplicates, you have to remove them first:

population = [1, 2, 3, 4, 5, 6, 5, 4, 3, 2, 1]
population = set(population)
samples = random.sample(population, 3)

这篇关于你如何选择“x"?Python中列表中唯一数字的数量?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！