不等式运算符是否比等式运算符更快? [英] Is the inequality operator faster than the equality operator?

问题描述

我知道这是一个微优化，所以我纯粹是出于好奇而询问.

I know this is a micro-optimization, so I ask out of pure curiosity.

从逻辑上讲，微处理器不需要比较相等运算符的两个操作数的所有位来确定FALSE"结果.

Logically, a microprocessor does not need to compare all the bits of both operands of an equality operator in order to determine a "FALSE" result.

注意，这与编程有关，因为它会影响程序的执行速度.

Note, this is programming-related because it affects the execution speed of a program.

推荐答案

通常，微处理器使用电门进行比较，而不是像这样一步一步地进行比较.它一次检查所有位.

Usually, the microprocessor does comparison using electrical gates and not step by step like that. It checks all bits at once.

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