中断并继续功能 [英] break and continue in function

问题描述

def funcA(i):
   if i%3==0:
      print "Oh! No!",
      print i
      break

for i in range(100):
   funcA(i)
   print "Pass",
   print i

我知道上面的脚本不起作用.那么，如果我需要将一个带有 break 或 continue 的函数放入循环中，我该怎么写?

I know script above won't work. So, how can I write if I need put a function with break or continue into a loop?

推荐答案

函数不能在调用它的代码中导致中断或继续.break/continue 必须字面上出现在循环内.您的选择是:

A function cannot cause a break or continue in the code from which it is called. The break/continue has to appear literally inside the loop. Your options are:

1. 从funcA返回一个值并用它来决定是否中断
2. 在 funcA 中引发异常并在调用代码(或调用链的更高位置)中捕获它
3. 编写一个封装中断逻辑的生成器，并在 range
上迭代它

#3 我的意思是这样的:

By #3 I mean something like this:

def gen(base):
    for item in base:
        if item%3 == 0:
           break
        yield i

for i in gen(range(1, 100)):
    print "Pass," i

这允许您通过将它们分组到基于基本"迭代器(在本例中为范围)的生成器中来放置条件中断.然后你迭代这个生成器而不是范围本身，你会得到破坏行为.

This allows you to put the break with the condition by grouping them into a generator based on the "base" iterator (in this case a range). You then iterate over this generator instead of over the range itself and you get the breaking behavior.

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