如何在字典列表中找到公共键的最小值/最大值? [英] How to find the min/max value of a common key in a list of dicts?

问题描述

我有一个像这样的字典列表:

I have a list of dictionaries like so:

[{'price': 99, 'barcode': '2342355'}, {'price': 88, 'barcode': '2345566'}]

我想找到 min() 和 max() 的价格.现在，我可以使用带有 lambda 表达式的键轻松地对其进行排序(如另一篇 Stack Overflow 帖子中所述)，因此如果没有其他方法，我不会被卡住.然而，据我所知，Python 中几乎总是有一种直接的方式，所以这是一个让我多学习一点的机会.

I want to find the min() and max() prices. Now, I can sort this easily enough using a key with a lambda expression (as found in another Stack Overflow post), so if there is no other way I'm not stuck. However, from what I've seen there is almost always a direct way in Python, so this is an opportunity for me to learn a bit more.

推荐答案

lst = [{'price': 99, 'barcode': '2342355'}, {'price': 88, 'barcode': '2345566'}]

maxPricedItem = max(lst, key=lambda x:x['price'])
minPricedItem = min(lst, key=lambda x:x['price'])

这不仅会告诉您最高价格是多少，还会告诉您哪个商品最贵.

This tells you not just what the max price is but also which item is most expensive.

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