如何在数组列表中找到最大值和最小值 [英] How to find the Max and min values in an arraylist

问题描述

我已经陷入了高中计算机科学家庭作业。这是一个小型的编程练习，问题是编写一个循环的Java代码，同时计算数组列表的最大值和最小值如果我能得到指导或甚至答案，我将不胜感激。

解决方案

基本代码，您必须以对象样式进行训练和写入。

 的ArrayList<整数> list = new ArrayList< Integer>（）; 
 list.add（8）; 
 list.add（-3）; 
 list.add（16）; 
 list.add（11）; 
 
 int min = list.get（0）; 
 int max = list.get（0）; （整数i：列表）{
 if（i  
 
 if（i> max）max = i; 
} 
 
 System.out.println（min =+ min）; 
 System.out.println（max =+ max）; 
  

如果您想使用简单的for循环：

  for（int i = 0; i< list.size（）; i ++）{
 int number = list.get（i）; 
 if（number  if（number> max）max = number; 
} 
  

I've become stumped in my high school computer science homework. It is a small programming exercise, the question being "Write java code for a loop that simultaneously computes the max and min values of an array list" If I can get guidance or maybe even an answer I would greatly appreciate it.

解决方案

Basic code, you must train and write this in object-style.

ArrayList<Integer> list = new ArrayList<Integer>();
list.add(8);
list.add(-3);
list.add(16);
list.add(11);

int min = list.get(0);
int max = list.get(0);

for(Integer i: list) {
    if(i < min) min = i;
    if(i > max) max = i;
}

System.out.println("min = " + min);
System.out.println("max = " + max);

if you want to work with a simple for loop :

for(int i = 0; i < list.size(); i++) {
    int number = list.get(i);
    if(number < min) min = number;
    if(number > max) max = number;
}

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