如何获取 URL 中最后一个斜杠后的所有内容? [英] How to get everything after last slash in a URL?

问题描述

如何在 Python 中提取 URL 中最后一个斜杠后面的内容?例如，这些 URL 应返回以下内容:

How can I extract whatever follows the last slash in a URL in Python? For example, these URLs should return the following:

URL: http://www.test.com/TEST1
returns: TEST1

URL: http://www.test.com/page/TEST2
returns: TEST2

URL: http://www.test.com/page/page/12345
returns: 12345

我已经尝试过 urlparse，但这给了我完整的路径文件名，例如 page/page/12345.

I've tried urlparse, but that gives me the full path filename, such as page/page/12345.

推荐答案

不需要花哨的东西，看标准库中的字符串方法，您可以轻松地在文件名"部分和其余部分之间拆分您的网址:

You don't need fancy things, just see the string methods in the standard library and you can easily split your url between 'filename' part and the rest:

url.rsplit('/', 1)

这样您就可以简单地获得您感兴趣的部分:

So you can get the part you're interested in simply with:

url.rsplit('/', 1)[-1]

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