如何通过最后一个斜杠分割路径? [英] How to split path by last slash?

问题描述

我有一个文件(比如名为 list.txt)，其中包含文件的相对路径，每行一个路径，例如:

I have a file (say called list.txt) that contains relative paths to files, one path per line, i.e. something like this:

foo/bar/file1
foo/bar/baz/file2
goo/file3

我需要编写一个 bash 脚本，一次处理一个路径，在最后一个斜杠处将其拆分，然后启动另一个进程，将路径的两个部分作为参数提供给它.到目前为止，我只有循环部分:

I need to write a bash script that processes one path at a time, splits it at the last slash and then launches another process feeding it the two pieces of the path as arguments. So far I have only the looping part:

for p in `cat list.txt`
do
   # split $p like "foo/bar/file1" into "foo/bar/" as part1 and "file1" as part2
   inner_process.sh $part1 $part2
done

我如何拆分?这在路径没有斜线的退化情况下是否有效?

How do I split? Will this work in the degenerate case where the path has no slashes?

推荐答案

使用 basename 和 dirname，这就是你所需要的.

Use basename and dirname, that's all you need.

part1=$(dirname "$p")
part2=$(basename "$p")

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