计算空格数，并在最后一个分割 [英] Count number of spaces, and split at the last one

问题描述

我有一个字符串simliar：

I have a string simliar to:

c:/folder name/somewhere/application.exe instanceName

（文件夹名称中的空格是有意的）我需要一种方法将它分成：

(n.b. the space in "folder name" is intentional) I need a way to split this into:

[0]c:/folder name/somewhere/application.exe
[1]instanceName

我将使用 split-path ，但显然有一个错误powershell v2阻止我这样做：

I was going to use split-path, but apparently there is a bug in powershell v2 that stops me doing this:

Split-Path : Cannot find drive. A drive with the name '

所以，我想如果我计算有多少空格，然后只需使用 -split（）将其分割到最后一个空格。
但是，我看不到如何计算空格数。
我发现了很多关于使用regex来计算复杂字符串的例子，但我只想计算空格。

So, I figured if I count how many spaces there are, and then simply use -split() to split it at the last space. But, I can't see how to count the number of spaces. I've found lots of examples that talk about using regex to count complex strings, but I just want to count spaces!

推荐答案

实现这一目标的方法我想象，但使用你的分裂的想法，你可以做以下。

Tonnes of ways to do this I imagine but to use your split idea you could do the following.

$split = "c:/folder name/somewhere/application.exe instanceName".Split(" ")
$path =  $split[0..($split.count -2)] -Join " "
$instance = $split[-1]

用空格分割sting。空格数由数组 $ split 中的字符串数表示。我们加入数组中的所有字符串接受最后一个int $ path ，然后我们取最后一个条目并将其分配给 $ instance

Split the sting by spaces. The number of spaces is represented by the count of strings in the array $split. We join all the strings in the array accept the last intp $path then we take the last entry and assign it to $instance

您也可以使用 .substring 和 .lastindexof

$string = "c:/folder name/somewhere/application.exe instanceName"
$index = $string.LastIndexOf(" ")
$string.Substring(0,$index)
$string.Substring($index + 1)

我看不到这种方式直接分割成一个数组在这个时候，但输出作为一个数组不会是一个大事。

I can't see a way to split this directly into an array at this time but outputing as an array would not be a big deal.

$path, $instance

或

$array = @($path,$instance)

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