如何在 Flask 中设置响应头? [英] How do I set response headers in Flask?
问题描述
这是我的代码:
@app.route('/hello', methods=["POST"])
def hello():
resp = make_response(render_template('hello.html'))
resp.headers['Access-Control-Allow-Origin'] = '*'
return resp
但是，当我从浏览器向我的服务器发出请求时，我收到此错误:
However, when I make a request from the browser to my server I get this error:
XMLHttpRequest cannot load http://localhost:5000/hello.
No 'Access-Control-Allow-Origin' header is present on the requested resource.
我也尝试过这种方法，将响应头设置为after"请求:
I have also tried this approach, setting the response headers "after" the request:
@app.after_request
def add_header(response):
response.headers['Access-Control-Allow-Origin'] = '*'
return response
没有骰子.我犯了同样的错误.有没有办法只在路由函数中设置响应头?这样的事情将是理想的:
No dice. I get the same error. Is there a way to just set the response headers in the route function? Something like this would be ideal:
@app.route('/hello', methods=["POST"])
def hello(response): # is this a thing??
response.headers['Access-Control-Allow-Origin'] = '*'
return response
但无论如何我都找不到这样做.请帮忙.
but I cant find anyway to do this. Please help.
编辑
如果我像这样使用 POST 请求来卷曲网址:
if I curl the url with a POST request like so:
curl -iX POST http://localhost:5000/hello
我收到了这个回复:
HTTP/1.0 500 INTERNAL SERVER ERROR
Content-Type: text/html
Content-Length: 291
Server: Werkzeug/0.9.6 Python/2.7.6
Date: Tue, 16 Sep 2014 03:58:42 GMT
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 3.2 Final//EN">
<title>500 Internal Server Error</title>
<h1>Internal Server Error</h1>
<p>The server encountered an internal error and was unable to complete your request. Either the server is overloaded or there is an error in the application.</p>
有什么想法吗?
推荐答案
你可以很容易地做到这一点:
You can do this pretty easily:
@app.route("/")
def home():
resp = flask.Response("Foo bar baz")
resp.headers['Access-Control-Allow-Origin'] = '*'
return resp
查看 flask.Response 和 flask.make_response()
但有些事情告诉我你还有另一个问题，因为 after_request 也应该正确处理它.
But something tells me you have another problem, because the after_request should have handled it correctly too.
编辑
我刚刚注意到您已经在使用 make_response 这是其中一种方法.就像我之前说的，after_request 应该也能工作.尝试通过 curl 访问端点并查看标头是什么:
EDIT
I just noticed you are already using make_response which is one of the ways to do it. Like I said before, after_request should have worked as well. Try hitting the endpoint via curl and see what the headers are:
curl -i http://127.0.0.1:5000/your/endpoint
你应该看到
> curl -i 'http://127.0.0.1:5000/'
HTTP/1.0 200 OK
Content-Type: text/html; charset=utf-8
Content-Length: 11
Access-Control-Allow-Origin: *
Server: Werkzeug/0.8.3 Python/2.7.5
Date: Tue, 16 Sep 2014 03:47:13 GMT
注意 Access-Control-Allow-Origin 标头.
Noting the Access-Control-Allow-Origin header.
编辑 2
正如我怀疑的那样，您得到了 500，所以您没有像想象的那样设置标题.在启动应用程序之前尝试添加 app.debug = True 并重试.您应该会得到一些显示问题根本原因的输出.
EDIT 2
As I suspected, you are getting a 500 so you are not setting the header like you thought. Try adding app.debug = True before you start the app and try again. You should get some output showing you the root cause of the problem.
例如:
@app.route("/")
def home():
resp = flask.Response("Foo bar baz")
user.weapon = boomerang
resp.headers['Access-Control-Allow-Origin'] = '*'
return resp
提供一个格式良好的 html 错误页面，在底部(对 curl 命令有用)
Gives a nicely formatted html error page, with this at the bottom (helpful for curl command)
Traceback (most recent call last):
...
File "/private/tmp/min.py", line 8, in home
user.weapon = boomerang
NameError: global name 'boomerang' is not defined
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