如何在Flask中设置响应头？ [英] How do I set response headers in Flask?
问题描述
这是我的代码：
@ app.route（'/ hello'，methods = [POST]）
def hello（）：
resp = make_response（）
resp.headers ['Access-Control-Allow-Origin'] ='*'
return resp
但是，当我从浏览器向我的服务器发出请求时，出现以下错误：
XMLHttpRequest无法加载http：// localhost：5000 / hello。
否请求的资源上存在Access-Control-Allow-Origin标题。
我也尝试了这种方法，在请求之后设置响应标头：
$ p $
@ app.after_request
def add_header（响应）：
response.headers ['Access-Control-Allow-Origin '] ='*'
返回响应
没有骰子。我犯了同样的错误。有没有办法在路由功能中设置响应头？这样的东西会是理想的：
$ p $ @ app.route（'/ hello'，methods = [POST]）
def hello（响应）：＃是这个东西吗？
response.headers ['Access-Control-Allow-Origin'] ='*'
返回响应
但无论如何我无法找到这样做。请帮忙。
编辑
像这样：
$ b $ pre $ curl -iX POST http：// localhost：5000 / hello
我得到这个回应：
pre $ HTTP $ / 1.0 500内部服务器错误
内容类型：text / html
内容长度：291
服务器：Werkzeug / 0.9.6 Python / 2.7.6
日期：星期二，16 9月2014 03:58:42 GMT
<！DOCTYPE HTML PUBLIC - // W3C // DTD HTML 3.2 Final // EN>
< title> 500内部伺服器错误< / title>
< h1>内部伺服器错误< / h1>
< p>服务器遇到内部错误，无法完成您的请求。服务器过载或应用程序出现错误。< / p>
有什么想法？
$ b
@ app.route（/）
def home（）：
resp = flask.Response（Foo bar baz）
resp.headers ['Access-Control-Allow-Origin'] ='*'
return resp
请看 flask.Response 和 flask.make_response（） a>
但是有些东西告诉我你还有另一个问题，因为 after_request 也应该正确处理它。 / b>
编辑
我刚注意到你已经在使用 make_response 这是做到这一点的方法之一。就像我之前说过的那样， after_request 应该也能工作。尝试通过curl点击端点并查看标题：
$ $ $ $ $ $ $ $ curl -i http://127.0.0.1:5000/您的/端点
您应该看到
> curl -i'http://127.0.0.1:5000/'
HTTP / 1.0 200 OK
Content-Type：text / html; charset = utf-8
Content-Length：11
Access-Control-Allow-Origin：*
服务器：Werkzeug / 0.8.3 Python / 2.7.5
日期：Tue ，2014年9月16日03:47:13 GMT
注意Access-Control-Allow-Origin标题。
编辑2
正如我怀疑，你得到了500，所以你不像你想象的设置标题。在启动应用程序之前，尝试添加 app.debug = True ，然后重试。例如：
您应该得到一些输出，显示问题的根源。 @ app.route（/）
def home（）：
resp = flask.Response（Foo bar baz）
user.weapon = boomerang
resp.headers ['Access-Control-Allow-Origin'] ='*'
return resp
给出一个格式良好的html错误页面，在底部（对curl命令有用）
$ p $ Traceback （最近一次调用最后一次）：
...
文件/private/tmp/min.py，第8行，在home
user.weapon = boomerang
NameError：全球名称boomerang未定义
This is my code:
@app.route('/hello', methods=["POST"])
def hello():
resp = make_response()
resp.headers['Access-Control-Allow-Origin'] = '*'
return resp
However, when I make a request from the browser to my server I get this error:
XMLHttpRequest cannot load http://localhost:5000/hello.
No 'Access-Control-Allow-Origin' header is present on the requested resource.
I have also tried this approach, setting the response headers "after" the request:
@app.after_request
def add_header(response):
response.headers['Access-Control-Allow-Origin'] = '*'
return response
No dice. I get the same error. Is there a way to just set the response headers in the route function? Something like this would be ideal:
@app.route('/hello', methods=["POST"])
def hello(response): # is this a thing??
response.headers['Access-Control-Allow-Origin'] = '*'
return response
but I cant find anyway to do this. Please help.
EDIT
if I curl the url with a POST request like so:
curl -iX POST http://localhost:5000/hello
I get this response:
HTTP/1.0 500 INTERNAL SERVER ERROR
Content-Type: text/html
Content-Length: 291
Server: Werkzeug/0.9.6 Python/2.7.6
Date: Tue, 16 Sep 2014 03:58:42 GMT
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 3.2 Final//EN">
<title>500 Internal Server Error</title>
<h1>Internal Server Error</h1>
<p>The server encountered an internal error and was unable to complete your request. Either the server is overloaded or there is an error in the application.</p>
Any ideas?
You can do this pretty easily:
@app.route("/")
def home():
resp = flask.Response("Foo bar baz")
resp.headers['Access-Control-Allow-Origin'] = '*'
return resp
Look at flask.Response and flask.make_response()
But something tells me you have another problem, because the after_request should have handled it correctly too.
EDIT
I just noticed you are already using make_response which is one of the ways to do it. Like I said before, after_request should have worked as well. Try hitting the endpoint via curl and see what the headers are:
curl -i http://127.0.0.1:5000/your/endpoint
You should see
> curl -i 'http://127.0.0.1:5000/'
HTTP/1.0 200 OK
Content-Type: text/html; charset=utf-8
Content-Length: 11
Access-Control-Allow-Origin: *
Server: Werkzeug/0.8.3 Python/2.7.5
Date: Tue, 16 Sep 2014 03:47:13 GMT
Noting the Access-Control-Allow-Origin header.
EDIT 2
As I suspected, you are getting a 500 so you are not setting the header like you thought. Try adding app.debug = True before you start the app and try again. You should get some output showing you the root cause of the problem.
For example:
@app.route("/")
def home():
resp = flask.Response("Foo bar baz")
user.weapon = boomerang
resp.headers['Access-Control-Allow-Origin'] = '*'
return resp
Gives a nicely formatted html error page, with this at the bottom (helpful for curl command)
Traceback (most recent call last):
...
File "/private/tmp/min.py", line 8, in home
user.weapon = boomerang
NameError: global name 'boomerang' is not defined
这篇关于如何在Flask中设置响应头？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
