如何使用 Bash 递归创建不存在的子目录? [英] How can I create nonexistent subdirectories recursively using Bash?

问题描述

我正在创建一个快速备份脚本，它将一些数据库转储到一个漂亮/整洁的目录结构中，我意识到我需要在创建目录之前进行测试以确保它们存在.我的代码有效，但有更好的方法吗?

I am creating a quick backup script that will dump some databases into a nice/neat directory structure and I realized that I need to test to make sure that the directories exist before I create them. The code I have works, but is there a better way to do it?

[ -d "$BACKUP_DIR" ] || mkdir "$BACKUP_DIR"
[ -d "$BACKUP_DIR/$client" ] || mkdir "$BACKUP_DIR/$client"
[ -d "$BACKUP_DIR/$client/$year" ] || mkdir "$BACKUP_DIR/$client/$year"
[ -d "$BACKUP_DIR/$client/$year/$month" ] || mkdir "$BACKUP_DIR/$client/$year/$month"
[ -d "$BACKUP_DIR/$client/$year/$month/$day" ] || mkdir "$BACKUP_DIR/$client/$year/$month/$day"

推荐答案

您可以使用 -p 参数，即 记录为:

You can use the -p parameter, which is documented as:

-p, --parents

-p, --parents

如果存在没有错误，根据需要制作父目录

no error if existing, make parent directories as needed

所以:

mkdir -p "$BACKUP_DIR/$client/$year/$month/$day"

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