使用 PHP 递归计算文件 [英] Recursively counting files with PHP

问题描述

对新手的简单问题，而我的 Google-Fu 却让我失望.使用 PHP，您如何计算给定目录中的文件数量，包括任何子目录(以及它们可能拥有的任何子目录等)?例如如果目录结构如下所示:

<前>/目录_A//Dir_A/File1.blah/Dir_A/Dir_B//Dir_A/Dir_B/File2.blah/Dir_A/Dir_B/File3.blah/Dir_A/Dir_B/Dir_C//Dir_A/Dir_B/Dir_C/File4.blah/Dir_A/Dir_D//Dir_A/Dir_D/File5.blah

对于./Dir_A"，脚本应该返回5".

我拼凑了以下内容，但没有完全返回正确答案，我不确定为什么:

<前>函数 getFilecount( $path = '.', $filecount = 0, $total = 0 ){$ignore = array( 'cgi-bin', '.', '..', '.DS_Store');$dh = @opendir( $path );while( false !== ( $file = readdir( $dh ) ) ){if( !in_array( $file, $ignore ) ){if(is_dir("$path/$file")){$filecount = count(glob( "$path/$file/" . "*"));$total += $filecount;回声$文件计数;/* 调试 */回声$总计"；/* 调试 */echo " $path/$file
";/* 调试 */getFilecount( "$path/$file", $filecount, $total);}}}返回 $total;}

非常感谢您的帮助.

解决方案

这应该可以解决问题:

function getFileCount($path) {$size = 0;$ignore = array('.','..','cgi-bin','.DS_Store');$files = scandir($path);foreach($files as $t) {if(in_array($t, $ignore)) 继续；if (is_dir(rtrim($path, '/') . '/' . $t)) {$size += getFileCount(rtrim($path, '/') . '/' . $t);} 别的 {$size++;}}返回 $size;}

Simple question for a newb and my Google-Fu is failing me. Using PHP, how can you count the number of files in a given directory, including any sub-directories (and any sub-directories they might have, etc.)? e.g. if directory structure looks like this:

/Dir_A/  
/Dir_A/File1.blah  
/Dir_A/Dir_B/  
/Dir_A/Dir_B/File2.blah  
/Dir_A/Dir_B/File3.blah  
/Dir_A/Dir_B/Dir_C/  
/Dir_A/Dir_B/Dir_C/File4.blah  
/Dir_A/Dir_D/  
/Dir_A/Dir_D/File5.blah

The script should return with '5' for "./Dir_A".

I've cobbled together the following but it's not quite returning the correct answer, and I'm not sure why:

function getFilecount( $path = '.', $filecount = 0, $total = 0 ){  
    $ignore = array( 'cgi-bin', '.', '..', '.DS_Store' );  
    $dh = @opendir( $path );  
    while( false !== ( $file = readdir( $dh ) ) ){  
        if( !in_array( $file, $ignore ) ){  
            if( is_dir( "$path/$file" ) ){  
                $filecount = count(glob( "$path/$file/" . "*"));  
                $total += $filecount;  
                echo $filecount; /* debugging */
                echo " $total"; /* debugging */
                echo " $path/$file
"; /* debugging */
                getFilecount( "$path/$file", $filecount, $total);  
            }  
        }  
    }  
    return $total;  
}  

I'd greatly appreciate any help.

解决方案

This should do the trick:

function getFileCount($path) {
    $size = 0;
    $ignore = array('.','..','cgi-bin','.DS_Store');
    $files = scandir($path);
    foreach($files as $t) {
        if(in_array($t, $ignore)) continue;
        if (is_dir(rtrim($path, '/') . '/' . $t)) {
            $size += getFileCount(rtrim($path, '/') . '/' . $t);
        } else {
            $size++;
        }   
    }
    return $size;
}

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