展开和匹配后的组数组 [英] Group array after unwind and match

问题描述

我有一个两次嵌套的架构:

I have a twice nested schema:

mongoose.model('Team', mongoose.Schema(
{
 players : [{ 
    trikots : [{
        isNew : Boolean,
        color : String
    }]
 }]
})

现在，我的查询如下所示:

For now, my query looks like this:

Team.aggregate()
        .match({'_id' : new ObjectId(teamId)})
        .unwind('players')
        .unwind('players.trikots')
        .match({'players.trikots.isNew' : 'red', 'players.trikots.isNew' : true})
        .exec(sendBack);

但我想要一个 Team 对象，它以数组的形式包含所有玩家.我怎样才能做到这一点?

But I would like to have one Team object, that contains all players as an array. How can I achieve that?

推荐答案

在 _id 上使用 Group 和 $push 运算符将所有玩家返回到一个数组中.

Use Group on _id with $push operator to return all players into an array.

Team.aggregate()
        .match({'_id' : new ObjectId(teamId)})
        .unwind('players')
        .unwind('players.trikots')
        .match({'players.trikots.color' : 'red', 'players.trikots.isNew' : true})
        .group({'_id':'$_id','players': {'$push': '$players'}})
        .exec(sendBack);

如果您希望在最终文档中包含任何其他字段，请在组操作期间将其添加到 _id 字段中.

If you want any other field to be included in the final doucment add it to _id field during group operation.

.group({'_id':{'_id':'$_id','some_other_field':'$some_other_field'},'players': {'$push': '$players'}})

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