在 C# 中检测系统从睡眠中唤醒的事件 [英] Event to detect System wake up from sleep in C#

问题描述

我需要检测系统电源状态模式.准确地说，我需要一个在 Windows 7 从睡眠中醒来时触发的事件.我已经在使用了:

I need to detect the system power state mode. To be precise, I need an event which fires up when windows 7 wakes up from sleep. I am already using:

SystemEvents.PowerModeChanged += SystemEvents_PowerModeChanged;

但是这个事件的问题是它被引发了四次:可能是在计算机进入睡眠模式和计算机唤醒之后.我想要一个仅在计算机唤醒时引发的事件.有什么活动吗?

But the problem with this event is that it is raised up four times: possibly when computer goes into sleep mode and after computer wakes up. I want an event which is raised at computer wake up only. Is there any event for this?

推荐答案

SystemEvents.PowerModeChanged += OnPowerChange;

private void OnPowerChange(object s, PowerModeChangedEventArgs e) 
{
    switch ( e.Mode ) 
    {
        case PowerModes.Resume: 
        break;
        case PowerModes.Suspend:
        break;
    }
}

您可能应该阅读以下内容:http://msdn.microsoft.com/en-us/library/microsoft.win32.systemevents.powermodechanged.aspx

You should probably read this: http://msdn.microsoft.com/en-us/library/microsoft.win32.systemevents.powermodechanged.aspx

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