事件检测系统从睡眠中唤醒C＃ [英] Event to detect System wake up from sleep in C#

问题描述

我需要检测系统电源状态模式。确切地说，当Windows 7从睡眠中醒来时，我需要一个触发的事件。我已经在使用：

I need to detect the system power state mode. To be precise, I need an event which fires up when windows 7 wakes up from sleep. I am already using:

SystemEvents.PowerModeChanged += SystemEvents_PowerModeChanged;

但是，这个事件的问题是提高了四次：可能当电脑进入睡眠状态模式和电脑唤醒后。我想要一个在电脑唤醒的事件。是否有任何事件？

But the problem with this event is that it is raised up four times: possibly when computer goes into sleep mode and after computer wakes up. I want an event which is raised at computer wake up only. Is there any event for this?

推荐答案

SystemEvents.PowerModeChanged += OnPowerChange;

private void OnPowerChange(object s, PowerModeChangedEventArgs e) 
{
    switch ( e.Mode ) 
    {
        case PowerModes.Resume: 
        break;
        case PowerModes.Suspend:
        break;
    }
}

你应该看这个：
< a href =http://msdn.microsoft.com/en-us/library/microsoft.win32.systemevents.powermodechanged.aspx =noreferrer> http://msdn.microsoft.com/en-us/ library / microsoft.win32.systemevents.powermodechanged.aspx

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