如何从 Json.NET 序列化的 JSON 恢复循环引用(例如“$id")? [英] How to restore circular references (e.g. "$id") from Json.NET-serialized JSON?

问题描述

是否有现有的 javascript 库可以通过引用循环处理反序列化 Json.Net?

Is there an existing javascript library which will deserialize Json.Net with reference loop handling?

{
    "$id": "1",
    "AppViewColumns": [
        {
            "$id": "2",
            "AppView": {"$ref":"1"},
            "ColumnID": 1,
        }
    ]
}

这应该反序列化为一个对象，在数组中的对象和外部对象之间有一个引用循环

this should deserialize to an object with a reference loop between the object in the array and the outer object

推荐答案

好的，所以我创建了一个更健壮的方法，它将使用 $id 和 $ref，因为这实际上是 json.net 处理循环引用的方式.此外，您必须在注册 id 后获取您的引用，否则它将找不到被引用的对象，因此我还必须保存请求引用的对象，以及他们想要设置的属性和 id他们正在请求.

Ok so I created a more robust method which will use $id as well as $ref, because that's actually how json.net handles circular references. Also you have to get your references after the id has been registered otherwise it won't find the object that's been referenced, so I also have to hold the objects that are requesting the reference, along with the property they want to set and the id they are requesting.

这严重基于 lodash/下划线

This is heavily lodash/underscore based

(function (factory) {
    'use strict';
    if (typeof define === 'function' && define.amd) {
        define(['lodash'], factory);
    } else {
        factory(_);
    }
})(function (_) {
    var opts = {
        refProp: '$ref',
        idProp: '$id',
        clone: true
    };
    _.mixin({
        relink: function (obj, optsParam) {
            var options = optsParam !== undefined ? optsParam : {};
            _.defaults(options, _.relink.prototype.opts);
            obj = options.clone ? _.clone(obj, true) : obj;
            var ids = {};
            var refs = [];
            function rl(s) {
                // we care naught about primitives
                if (!_.isObject(s)) {
                    return s;
                }
                if (s[options.refProp]) {
                    return null;
                }
                if (s[options.idProp] === 0 || s[options.idProp]) {
                    ids[s[options.idProp]] = s;
                }
                delete s[options.idProp];
                _(s).pairs().each(function (pair) {
                    if (pair[1]) {
                        s[pair[0]] = rl(pair[1]);
                        if (s[pair[0]] === null) {
                            if (pair[1][options.refProp] !== undefined) {
                                refs.push({ 'parent': s, 'prop': pair[0], 'ref': pair[1][options.refProp] });
                            }
                        }
                    }
                });

                return s;
            }

            var partialLink = rl(obj);
            _(refs).each(function (recordedRef) {
                recordedRef['parent'][recordedRef['prop']] = ids[recordedRef['ref']] || {};
            });
            return partialLink;
        },
        resolve: function (obj, optsParam) {
            var options = optsParam !== undefined ? optsParam : {};
            _.defaults(options, _.resolve.prototype.opts);
            obj = options.clone ? _.clone(obj, true) : obj;
            var objs = [{}];

            function rs(s) {
                // we care naught about primitives
                if (!_.isObject(s)) {
                    return s;
                }
                var replacementObj = {};

                if (objs.indexOf(s) != -1) {
                    replacementObj[options.refProp] = objs.indexOf(s);
                    return replacementObj;
                }
                objs.push(s);
                s[options.idProp] = objs.indexOf(s);
                _(s).pairs().each(function (pair) {
                    s[pair[0]] = rs(pair[1]);
                });

                return s;
            }

            return rs(obj);
        }
    });
    _(_.resolve.prototype).assign({ opts: opts });
    _(_.relink.prototype).assign({ opts: opts });
});

我在这里创建了一个要点

这篇关于如何从 Json.NET 序列化的 JSON 恢复循环引用(例如“$id")?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！