使用索引获取项目 [英] Using an index to get an item

问题描述

我在 python 中有一个列表 ('A','B','C','D','E')，如何获取特定索引号下的项目?

I have a list in python ('A','B','C','D','E'), how do I get which item is under a particular index number?

示例:

• 假设它被赋予 0，它会返回 A.
• 给定 2，它将返回 C.
• 给定 4，它将返回 E.

推荐答案

What you show, ('A','B','C','D','E'),不是 list，它是一个 tuple(圆括号而不是方括号表明了这一点).然而，无论是索引列表还是元组(用于在索引处获取一个项目)，在任何一种情况下，您都将索引附加在方括号中.

What you show, ('A','B','C','D','E'), is not a list, it's a tuple (the round parentheses instead of square brackets show that). Nevertheless, whether it to index a list or a tuple (for getting one item at an index), in either case you append the index in square brackets.

所以:

thetuple = ('A','B','C','D','E')
print thetuple[0]

打印A，等等.

元组(不同于列表)是不可变的，所以你不能赋值给thetuple[0]等(你可以赋值到列表的索引).但是，在任何一种情况下，您都可以通过索引直接访问(获取")该项目.

Tuples (differently from lists) are immutable, so you couldn't assign to thetuple[0] etc (as you could assign to an indexing of a list). However you can definitely just access ("get") the item by indexing in either case.

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