使用索引获取项目,Python [英] Using an index to get an item, Python
问题描述
我在python中有一个列表('A','B','C','D','E'),我如何获得特定索引号下的项目?
I have a list in python ('A','B','C','D','E'), how do I get which item is under a particular index number?
示例:
假设它被赋予0,它将返回A.
给定2,它将返回C.
给定4 ,它会返回E。
Example: Say it was given 0, it would return A. Given 2, it would return C. Given 4, it would return E.
推荐答案
你展示的是什么,('A','B', 'C','D','E')
,不是列表
,它是元组
(圆括号而不是方括号表示)。然而,无论是索引列表还是一个元组(用于在索引处获取一个项目),在任何一种情况下都将索引附加在方括号中。
What you show, ('A','B','C','D','E')
, is not a list
, it's a tuple
(the round parentheses instead of square brackets show that). Nevertheless, whether it to index a list or a tuple (for getting one item at an index), in either case you append the index in square brackets.
所以:
thetuple = ('A','B','C','D','E')
print thetuple[0]
打印 A
,等等。
元组(与列表不同)是不可变的,所以你不能将分配给 thetuple [0]
等(因为您可以分配给列表的索引)。但是,您无论如何都可以通过索引来只访问(获取)项目。
Tuples (differently from lists) are immutable, so you couldn't assign to thetuple[0]
etc (as you could assign to an indexing of a list). However you can definitely just access ("get") the item by indexing in either case.
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