在 dplyr mutate() 中返回一个列表 [英] Return a list in dplyr mutate()

问题描述

我的实际问题中有一个函数可以返回一个列表.有没有办法将它与 dplyr mutate() 一起使用?这个玩具示例不起作用 -:

I have a function in my real-world problem that returns a list. Is there any way to use this with the dplyr mutate()? This toy example doesn't work -:

it = data.table(c("a","a","b","b","c"),c(1,2,3,4,5), c(2,3,4,2,2))

myfun = function(arg1,arg2) {

temp1 = arg1 + arg2
temp2 = arg1 - arg2
list(temp1,temp2)

}

myfun(1,2)

it%.%mutate(new = myfun(V2,V3))

我看到它在 new 变量的第一个列"中循环遍历函数的输出，但不明白为什么.

I see that it is cycling through the output of the function in the first "column" of the new variable, but do not understand why.

谢谢！

推荐答案

使用 data.table 执行此操作的惯用方法是使用 :=(赋值通过引用)运算符.这是一个插图:

The idiomatic way to do this using data.table would be to use the := (assignment by reference) operator. Here's an illustration:

it[, c(paste0("V", 4:5)) := myfun(V2, V3)]

<小时>

如果你真的想要一个列表，为什么不:

---

If you really want a list, why not:

as.list(it[, myfun(V2, V3)])

或者，也许这就是您想要的，但您为什么不直接使用 data.table 功能:

Alternatively, maybe this is what you want, but why don't you just use the data.table functionality:

it[, c(.SD, myfun(V2, V3))]
#    V1 V2 V3 V4 V5
# 1:  a  1  2  3 -1
# 2:  a  2  3  5 -1
# 3:  b  3  4  7 -1
# 4:  b  4  2  6  2
# 5:  c  5  2  7  3    

请注意，如果 myfun 将其命名为输出，则名称将显示在最终结果列中:

Note that if myfun were to name it's output, then the names would show up in the final result columns:

#    V1 V2 V3 new.1 new.2
# 1:  a  1  2     3    -1
# 2:  a  2  3     5    -1
# 3:  b  3  4     7    -1
# 4:  b  4  2     6     2
# 5:  c  5  2     7     3    

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