如何将 mysqli 结果转换为 JSON? [英] How to convert mysqli result to JSON?

问题描述

我有一个 mysqli 查询，我需要将其格式化为移动应用程序的 JSON.

我已经设法为查询结果生成了一个 XML 文档，但是我正在寻找更轻量级的东西.(请参阅下面我当前的 XML 代码)

$mysql = new mysqli(DB_SERVER,DB_USER,DB_PASSWORD,DB_NAME) or die('连接数据库时出现问题');$stmt = $mysql->prepare('SELECT DISTINCT title FROM Section ORDER BY title ASC');$stmt->execute();$stmt->bind_result($title);//创建xml格式$doc = new DomDocument('1.0');//创建根节点$root = $doc->createElement('xml');$root = $doc->appendChild($root);//为每一行添加节点while($row = $stmt->fetch()) :$occ = $doc->createElement('data');$occ = $root->appendChild($occ);$child = $doc->createElement('section');$child = $occ->appendChild($child);$value = $doc->createTextNode($title);$value = $child->appendChild($value);终了；$xml_string = $doc->saveXML();header('Content-Type: application/xml; charset=ISO-8859-1');//输出 xml jQuery 就绪回声 $xml_string;

解决方案

$mysqli = new mysqli('localhost','user','password','myDatabaseName');$myArray = array();if ($result = $mysqli->query("SELECT * FROM phase1")) {while($row = $result->fetch_array(MYSQLI_ASSOC)) {$myArray[] = $row;}回声 json_encode($myArray);}$result->close();$mysqli->close();

1. $row = $result->fetch_array(MYSQLI_ASSOC)
2. $myArray[] = $row

输出如下:

<预><代码>[{"id":"31","name":"pruduct_name1","price":"98"},{"id":"30","name":"pruduct_name2","price":"23"}]

如果你想要另一种风格，你可以试试这个:

1. $row = $result->fetch_row()
2. $myArray[] = $row

输出如下:

<预><代码>[["31","pruduct_name1","98"],["30","pruduct_name2","23"]]

I have a mysqli query which I need to format as JSON for a mobile application.

I have managed to produce an XML document for the query results, however I am looking for something more lightweight. (See below for my current XML code)

$mysql = new mysqli(DB_SERVER,DB_USER,DB_PASSWORD,DB_NAME) or die('There was a problem connecting to the database');

$stmt = $mysql->prepare('SELECT DISTINCT title FROM sections ORDER BY title ASC');
$stmt->execute();
$stmt->bind_result($title);

// create xml format
$doc = new DomDocument('1.0');

// create root node
$root = $doc->createElement('xml');
$root = $doc->appendChild($root);

// add node for each row
while($row = $stmt->fetch()) : 

    $occ = $doc->createElement('data');  
    $occ = $root->appendChild($occ);  

    $child = $doc->createElement('section');  
    $child = $occ->appendChild($child);  
    $value = $doc->createTextNode($title);  
    $value = $child->appendChild($value);  

endwhile;

$xml_string = $doc->saveXML();  

header('Content-Type: application/xml; charset=ISO-8859-1');

// output xml jQuery ready

echo $xml_string;

解决方案

$mysqli = new mysqli('localhost','user','password','myDatabaseName');
$myArray = array();
if ($result = $mysqli->query("SELECT * FROM phase1")) {

    while($row = $result->fetch_array(MYSQLI_ASSOC)) {
            $myArray[] = $row;
    }
    echo json_encode($myArray);
}

$result->close();
$mysqli->close();

1. $row = $result->fetch_array(MYSQLI_ASSOC)
2. $myArray[] = $row

output like this:

[
    {"id":"31","name":"pruduct_name1","price":"98"},
    {"id":"30","name":"pruduct_name2","price":"23"}
]

If you want another style, you can try this:

1. $row = $result->fetch_row()
2. $myArray[] = $row

output will like this:

[
    ["31","pruduct_name1","98"],
    ["30","pruduct_name2","23"]
]

这篇关于如何将 mysqli 结果转换为 JSON?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！