报告服务部署 [英] Reporting Services Deployment

问题描述

我需要创建一个可重复的过程来部署 SQL Server Reporting Services 报告.我不赞成使用 Visual Studio 或 Business Development Studio 来执行此操作.脚本部署的 rs.exe 方法也显得相当笨拙.有没有人有一种非常优雅的方式来部署报告.这里的关键是我希望这个过程完全自动化.

I need to create a repeatable process for deploying SQL Server Reporting Services reports. I am not in favor of using Visual Studio and or Business Development Studio to do this. The rs.exe method of scripting deployments also seems rather clunky. Does anyone have a very elegant way that they have been able to deploy reports. The key here is that I want the process to be completely automated.

推荐答案

我们使用 rs.exe，一旦我们开发了脚本，我们就不需要再碰它了，它就可以工作了.

We use rs.exe, once we developed the script we have not needed to touch it anymore, it just works.

这是源代码(我手动稍微修改了它以删除敏感数据而没有机会测试它，希望我没有刹车任何东西)，它从各种语言的子目录中部署报告和相关图像.还创建了数据源.

Here is the source (I slightly modified it by hand to remove sensitive data without a chance to test it, hope I did not brake anything), it deploys reports and associated images from subdirectories for various languages. Also datasource is created.

'=====================================================================
'  File:      PublishReports.rss
'
'  Summary: Script that can be used with RS.exe to 
'           publish the reports.
'
'  Rss file spans from beginnig of this comment to end of module
' (except of "End Module").
'=====================================================================

Dim langPaths As String() = {"en", "cs", "pl", "de"}
Dim filePath As String = Environment.CurrentDirectory

Public Sub Main()

    rs.Credentials = System.Net.CredentialCache.DefaultCredentials

    'Create parent folder
    Try
        rs.CreateFolder(parentFolder, "/", Nothing)
        Console.WriteLine("Parent folder created: {0}", parentFolder)
    Catch e As Exception
        Console.WriteLine(e.Message)
    End Try

    PublishLanguagesFromFolder(filePath)

End Sub

Public Sub PublishLanguagesFromFolder(ByVal folder As String)
    Dim Lang As Integer
    Dim langPath As String

    For Lang = langPaths.GetLowerBound(0) To langPaths.GetUpperBound(0)
        langPath = langPaths(Lang)

        'Create the lang folder
        Try
            rs.CreateFolder(langPath, "/" + parentFolder, Nothing)
            Console.WriteLine("Parent lang folder created: {0}", parentFolder + "/" + langPath)
        Catch e As Exception
            Console.WriteLine(e.Message)
        End Try

        'Create the shared data source
        CreateDataSource("/" + parentFolder + "/" + langPath)

        'Publish reports and images
        PublishFolderContents(folder + "" + langPath, "/" + parentFolder + "/" + langPath)
    Next 'Lang
End Sub

Public Sub CreateDataSource(ByVal targetFolder As String)
    Dim name As String = "data source"

    'Data source definition.
    Dim definition As New DataSourceDefinition
    definition.CredentialRetrieval = CredentialRetrievalEnum.Store
    definition.ConnectString = "data source=" + dbServer + ";initial catalog=" + db
    definition.Enabled = True
    definition.EnabledSpecified = True
    definition.Extension = "SQL"
    definition.ImpersonateUser = False
    definition.ImpersonateUserSpecified = True
    'Use the default prompt string.
    definition.Prompt = Nothing
    definition.WindowsCredentials = False
    'Login information
    definition.UserName = "user"
    definition.Password = "password"

    Try
    'name, folder, overwrite, definition, properties 
        rs.CreateDataSource(name, targetFolder, True, definition, Nothing)
    Catch e As Exception
        Console.WriteLine(e.Message)
    End Try

End Sub

Public Sub PublishFolderContents(ByVal sourceFolder As String, ByVal targetFolder As String)
    Dim di As New DirectoryInfo(sourceFolder)
    Dim fis As FileInfo() = di.GetFiles()
    Dim fi As FileInfo

    Dim fileName As String

    For Each fi In fis
        fileName = fi.Name
        Select Case fileName.Substring(fileName.Length - 4).ToUpper
            Case ".RDL"
                PublishReport(sourceFolder, fileName, targetFolder)
            Case ".JPG", ".JPEG"
                PublishResource(sourceFolder, fileName, "image/jpeg", targetFolder)
            Case ".GIF", ".PNG", ".BMP"
                PublishResource(sourceFolder, fileName, "image/" + fileName.Substring(fileName.Length - 3).ToLower, targetFolder)
        End Select
    Next fi
End Sub

Public Sub PublishReport(ByVal sourceFolder As String, ByVal reportName As String, ByVal targetFolder As String)
    Dim definition As [Byte]() = Nothing
    Dim warnings As Warning() = Nothing

    Try
        Dim stream As FileStream = File.OpenRead(sourceFolder + "" + reportName)
        definition = New [Byte](stream.Length) {}
        stream.Read(definition, 0, CInt(stream.Length))
        stream.Close()
    Catch e As IOException
        Console.WriteLine(e.Message)
    End Try

    Try
   'name, folder, overwrite, definition, properties 
        warnings = rs.CreateReport(reportName.Substring(0, reportName.Length - 4), targetFolder, True, definition, Nothing)

        If Not (warnings Is Nothing) Then
            Dim warning As Warning
            For Each warning In warnings
                Console.WriteLine(warning.Message)
            Next warning
        Else
            Console.WriteLine("Report: {0} published successfully with no warnings", targetFolder + "/" + reportName)
        End If
    Catch e As Exception
        Console.WriteLine(e.Message)
    End Try
End Sub

Public Sub PublishResource(ByVal sourceFolder As String, ByVal resourceName As String, ByVal resourceMIME As String, ByVal targetFolder As String)
    Dim definition As [Byte]() = Nothing
    Dim warnings As Warning() = Nothing

    Try
        Dim stream As FileStream = File.OpenRead(sourceFolder + "" + resourceName)
        definition = New [Byte](stream.Length) {}
        stream.Read(definition, 0, CInt(stream.Length))
        stream.Close()
    Catch e As IOException
        Console.WriteLine(e.Message)
    End Try

    Try
    'name, folder, overwrite, definition, MIME, properties 
        rs.CreateResource(resourceName, targetFolder, True, definition, resourceMIME, Nothing)
        Console.WriteLine("Resource: {0} with MIME {1} created successfully", targetFolder + "/" + resourceName, resourceMIME)
    Catch e As Exception
        Console.WriteLine(e.Message)
    End Try
End Sub

这是调用 rs.exe 的批处理:

Here is the batch to call the rs.exe:

SET ReportServer=%1
SET DBServer=%2
SET DBName=%3
SET ReportFolder=%4

rs -i PublishReports.rss -s %ReportServer% -v dbServer="%DBServer%" -v db="%DBName%" -v parentFolder="%ReportFolder%" >PublishReports.log 2>&1

pause

这篇关于报告服务部署的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！