在批处理文件中最后一个分隔符实例之后提取字符串 [英] Extracting string after last instance of delimiter in a Batch file

问题描述

我正在编写一个由 Java 程序调用的 Windows 批处理文件.许多表示文件目录的不同字符串作为参数传递到批处理文件中.我想弄清楚如何在"的最后一个实例之后提取一个字符串.比如我有三个目录:

I'm working on writing a Windows batch file that is called by a Java program. A number of different strings denoting file directories are passed into the batch file as parameters. I am trying to figure out how to extract a string after the last instance of the "". For example, I have three directories:

C:UsersownerDocuments
C:UsersownerVideos
C:UsersownerPicturesTrip

我想拆分它，使字符串变成:

I would like to split it so that the strings become:

Documents
Videos
Trip

你们如何建议我这样做?

How would you guys suggest I do this?

这里提出了一个后续问题:Windows 批处理文件中的 For 循环:错误:命令的语法不正确"

A follow-up question has been asked here: For loop in Windows batch file: Error: "The syntax of the command is incorrect"

推荐答案

给param"变量赋值一个参数后，使用:

After assigned one parameter to "param" variable, use:

for %%a in (%param:= %) do set lastDir=%%a

只要最后一个目录没有空格，这个方法就有效.如果需要，可以修复此细节.所有参数的处理是这样的:

This method works as long as the last directory does NOT have spaces. This detail may be fixed, if needed. The processing of all parameters would be like this:

:nextParam
   set "param=%~1"
   if not defined param goto endParams
   for %%a in (%param:= %) do set lastDir=%%a
   echo Last dir: %lastDir%
   shift
goto nextParam
:endParams

或者，以更简单的方式(没有空格限制):

Or, in a simpler way (with no spaces restrictions):

:nextParam
   if "%~1" equ "" goto endParams
   echo Last dir: %~N1
   shift
goto nextParam
:endParams

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