在批处理文件分隔符的最后一个实例后提取字符串 [英] Extracting string after last instance of delimiter in a Batch file

问题描述

我正在写一个由Java程序被称为Windows批处理文件。许多不同的字符串表示文件的目录传递到批处理文件作为参数。我试图找出如何的\\的最后一个实例后提取的字符串。例如，我有三个目录：

I'm working on writing a Windows batch file that is called by a Java program. A number of different strings denoting file directories are passed into the batch file as parameters. I am trying to figure out how to extract a string after the last instance of the "\". For example, I have three directories:

C:\Users\owner\Documents
C:\Users\owner\Videos
C:\Users\owner\Pictures\Trip

我想拆分它，使字符串变成了：

I would like to split it so that the strings become:

Documents
Videos
Trip

你们会如何建议我这样做呢？

How would you guys suggest I do this?

编辑：一个后续问题已经被问这里：<一href=\"http://stackoverflow.com/questions/20010117/for-loop-in-windows-batch-file-error-the-syntax-of-the-command-is-incorrect\">For循环在Windows批处理文件：错误：＆QUOT;该命令的语法不正确＆QUOT;

A follow-up question has been asked here: For loop in Windows batch file: Error: "The syntax of the command is incorrect"

推荐答案

指定一个参数后，参数变量，使用：

After assigned one parameter to "param" variable, use:

for %%a in (%param:\= %) do set lastDir=%%a

作为最后一个目录没有空间，此方法效果一样长。这一细节可以是固定的，如果需要的话。所有参数的处理会是这样的：

This method works as long as the last directory does NOT have spaces. This detail may be fixed, if needed. The processing of all parameters would be like this:

:nextParam
   set "param=%~1"
   if not defined param goto endParams
   for %%a in (%param:\= %) do set lastDir=%%a
   echo Last dir: %lastDir%
   shift
goto nextParam
:endParams

或者，在一个简单的方法（不带空格限制）：

Or, in a simpler way (with no spaces restrictions):

:nextParam
   if "%~1" equ "" goto endParams
   echo Last dir: %~N1
   shift
goto nextParam
:endParams

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