如何生成 R 计数矩阵 [英] How to produce an R count matrix
本文介绍了如何生成 R 计数矩阵的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
在 R 中,我可以使用我感兴趣的特定列名作为数组返回计数结果,如下所示.
In R, I can return the count results using the specific column names I am interested in as an array as below.
require("plyr")
bevs <- data.frame(cbind(name = c("Bill", "Llib"), drink = c("coffee", "tea", "cocoa", "water"), cost = seq(1:8)))
count(bevs, c("name", "drink"))
# produces
name drink freq
1 Bill cocoa 2
2 Bill coffee 2
3 Llib tea 2
4 Llib water 2
如何获得矩阵中两个特定列名称的计数结果,该矩阵具有列:所有独特的饮料,行:所有独特的名称和单元格:频率(如下所示)?
How can I get the count result of two specific column names in a matrix which has columns: all unique drinks, rows: all unique names and cells: freqs (like below)?
cocoa coffee tea water
Bill 2 2 0 0
Llib 0 0 2 2
P.S:显然,解决方案不需要使用plyr.
P.S: Obviously, the solution does not need to use plyr.
推荐答案
您需要一个列联表,可以使用 table
创建:
You want a contingency table, which you can create using table
:
table(bevs[, c("name", "drink")])
# drink
#name cocoa coffee tea water
# Bill 2 2 0 0
# Llib 0 0 2 2
这篇关于如何生成 R 计数矩阵的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文