UNIX 编程.struct timeval 如何打印它(C 编程) [英] UNIX Programming. struct timeval how to print it (C-programming)
问题描述
我正在尝试打印 timeval 类型的值.实际上我可以打印它,但我收到以下警告:
I am trying to print a value of type timeval. Actually I am able to print it, but I get the following warning:
此行有多个标记
- 格式%ld"需要类型long int",但参数 2 的类型为struct timeval"
程序编译并打印值,但我想知道我是否做错了什么.谢谢.
The program compiles and it prints the values, but I would like to know if I am doing something wrong. Thanks.
printf("%ld.%6ld
",usage.ru_stime);
printf("%ld.%6ld
",usage.ru_utime);
使用类型
typedef struct{
struct timeval ru_utime; /* user time used */
struct timeval ru_stime; /* system time used */
long ru_maxrss; /* maximum resident set size */
long ru_ixrss; /* integral shared memory size */
long ru_idrss; /* integral unshared data size */
long ru_isrss; /* integral unshared stack size */
long ru_minflt; /* page reclaims */
long ru_majflt; /* page faults */
long ru_nswap; /* swaps */
long ru_inblock; /* block input operations */
long ru_oublock; /* block output operations */
long ru_msgsnd; /* messages sent */
long ru_msgrcv; /* messages received */
long ru_nsignals; /* signals received */
long ru_nvcsw; /* voluntary context switches */
long ru_nivcsw; /* involuntary context switches */
}rusage;
struct rusage usage;
推荐答案
在 GNU C 库中,struct timeval
:
在 sys/time.h 中声明并具有以下成员:
is declared in sys/time.h and has the following members:
long int tv_sec
这表示经过的时间的整秒数.
This represents the number of whole seconds of elapsed time.
long int tv_usec
这是剩余的经过时间(几分之一秒),以微秒数表示.总是少于一百万.
This is the rest of the elapsed time (a fraction of a second), represented as the number of microseconds. It is always less than one million.
所以你需要这样做
printf("%ld.%06ld
", usage.ru_stime.tv_sec, usage.ru_stime.tv_usec);
获得格式良好"的时间戳,例如 1.000123
.
to get a "nicely formatted" timestamp like 1.000123
.
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