Unix Shell编程：打印时添加一个空行 [英] Unix Shell Programming: Add a blank line when printing

问题描述

我试图列出目录中的所有文件，但是如何以空行分隔每个文件？基本上每个文件显示由一个空行分隔？我正在尝试使用for循环？我做了几个例子，但没有真正的工作间隔一个空行吗？

 为我在ls 
做
回声\ n&& ls -l 
完成
 
为ls 
做
 echo\\\

 ls 
完成
  

解决方案

  find -printf'％p \\\
\\\
'
  

一个稍微差一点的（但更便携的）：

  ls | sed's | $ | \\\
 |'
  

更复杂的一个：

  ls |同时读f;做
 echo$ f
 echo 
 done 
  

这是什么 你永远不应该做的： ：

  for`ls`中的f; do 
 echo $ f 
 echo 
 done 
 code 
 
 
 
编辑： 
 
 
而且，正如
  for f in *;做
回声$ f
 echo 
完成
  
其中一个缺点是默认情况下，在许多shell  * 中展开为自身，而不存在文件时为空字符串。
 
I am trying to list all the files in the directory but how would you separate each of the files by a blank line? basically each file displayed by separated by a blank line? I am trying to use a for loop? I did try few examples but none really work by spacing a blank lines in between?
for i in ls  
do
echo "\n" && ls -l
done

for i in ls  
do
echo "\n" 
ls 
done

解决方案
Here's one:
find -printf '%p\n\n'
A slightly worse (but more portable) one:
ls | sed 's|$|\n|'
A more convoluted one:
ls | while read f; do
    echo "$f"
    echo
done
And here is what you should not ever do:
for f in `ls`; do
    echo "$f"
    echo
done
EDIT:

And, as mentioned by Nija, the simple shell-only one:
for f in *; do
    echo "$f"
    echo
done
This one has the disadvantage that on many shells * by default expands to itself, rather than an empty string when no files exist.

                        
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