F# 中的函数应用运算符 ($)? [英] Function Application Operator ($) in F#?

问题描述

假设我有这个代码

let identifier = spaces_surrounded (many1Satisfy isLetter)

我想知道是否有任何原生 F# 函数允许我将其重构为

I was wondering if it there was any native F# function that allowed me to refactor it to

let identifier = spaces_surrounded $ many1Satisfy isLetter

也就是说，诸如

let ($) f1 f2 = f1 (f2)

(也就是说如果我没记错的话，我的 Haskell 技能还不算太敏锐..).​​

(that is if I am not mistaken, my Haskell skills are not too sharp..).

推荐答案

用于此的标准 F# 习语是前向管道运算符 |> 如果您要重写

The standard F# idiom for this is the forward pipe operator |> were you would rewrite

let identifier = spaces_surrounded (many1Satisfy isLetter)

作为

let identifier = many1Satisfy isLetter |> spaces_surrounded 

如果你想保持原来的顺序，你也可以使用反向管道操作符<|，但这往往不太常见

you can also use the backward pipe operator <| if you want to maintain the original order, but this tends to be a little less common

let identifier = spaces_surrounded <| many1Satisfy isLetter

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