批处理文件 - 命令行参数的数量 [英] Batch files - number of command line arguments
问题描述
只是将一些 shell 脚本转换为批处理文件，我似乎找不到一件事……那就是对命令行参数数量的简单计数.
Just converting some shell scripts into batch files and there is one thing I can't seem to find...and that is a simple count of the number of command line arguments.
例如.如果你有:
myapp foo bar
在壳中:
- $# -> 2
- $* -> foo bar
- $0 -> myapp
- $1 -> foo
- $2 -> bar
批量处理
- ??-> 2 <---- 什么命令?！
- %* -> foo bar
- %0 -> 我的应用
- %1 -> foo
- %2 -> 条形
所以我环顾四周，要么是看错了地方，要么是瞎了眼，但我似乎找不到一种方法来计算传入的命令行参数的数量.
So I've looked around, and either I'm looking in the wrong spot or I'm blind, but I can't seem to find a way to get a count of number of command line arguments passed in.
有没有类似于shell的$#"的批处理文件的命令?
Is there a command similar to shell's "$#" for batch files?
ps.我发现的最接近的是遍历 %1s 并使用shift"，但我需要稍后在脚本中引用 %1、%2 等，这样不好.
ps. the closest i've found is to iterate through the %1s and use 'shift', but I need to refernece %1,%2 etc later in the script so that's no good.
推荐答案
谷歌搜索一下会得到以下结果来自 维基书籍:
Googling a bit gives you the following result from wikibooks:
set argC=0
for %%x in (%*) do Set /A argC+=1
echo %argC%
似乎 cmd.exe 已经从旧的 DOS 时代进化了一些 :)
Seems like cmd.exe has evolved a bit from the old DOS days :)
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