批处理文件 - 一些命令行参数 [英] Batch files - number of command line arguments
问题描述
只是把一些shell脚本到批处理文件和有一件事我似乎无法找到...这是命令行参数的数量的简单计数。
Just converting some shell scripts into batch files and there is one thing I can't seem to find...and that is a simple count of the number of command line arguments.
如。如果您有：
myapp foo bar
在壳牌：
- $＃ - > 2
- $ * - >富栏
- $ 0 - >的myapp </ li>
- $ 1 - >富
- $ 2 - >栏
在批
- ？ ？！ - > 2'; ----什么命令
- ％* - >富栏
- ％0 - >的myapp </ li>
- ％1 - >富
- 2％ - >栏
所以，我环顾四周，无论是和我看在错误的地方或者我是盲人，但我似乎无法找到一种方式来获得的传入的命令行参数的个数计数。
So I've looked around, and either I'm looking in the wrong spot or I'm blind, but I can't seem to find a way to get a count of number of command line arguments passed in.
有没有类似shell的$＃批处理文件？
Is there a command similar to shell's "$#" for batch files?
PS。我发现的最接近的是通过1秒％迭代，并使用'转移'，但我需要在脚本中2等以后refernece％1％所以这是没有好。
ps. the closest i've found is to iterate through the %1s and use 'shift', but I need to refernece %1,%2 etc later in the script so that's no good.
推荐答案
谷歌上搜索了一下给你来自的维基：
Googling a bit gives you the following result from wikibooks:
set argC=0
for %%x in (%*) do Set /A argC+=1
echo %argC%
好像cmd.exe的演变从旧的DOS时代了一下：）
Seems like cmd.exe has evolved a bit from the old DOS days :)
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