在 F# 中 >>运营商是什么意思? [英] In F# what does the >> operator mean?
问题描述
我在此示例中的一些代码中注意到 包含 >> 运算符:
让 printTree =树 >>Seq.iter (Seq.fold (+) "" >> printfn "%s")
>> 运算符是什么意思/做什么?
非常感谢,现在清楚多了.这是我为掌握它而生成的示例:
开放系统打开 System.IOlet read_lines path = File.ReadAllLines(path) |>Array.to_list让修剪线 = (字符串线).Trim()让 to_upper line = (string line).ToUpper()let new_list = [ for line in read_lines "myText.txt" ->线|>(修剪 >> to_upper) ]printf "%A" new_list
是函数组合运算符.
有关Chris Smith 的博文的更多信息.
<块引用>函数组成介绍运算符 (>>):
let inline (>>) f g x = g(f x)
读作:给定两个函数,f和 g,以及一个值 x,计算x 的 f 的结果并通过该结果到 g.这里有趣的是你可以咖喱 (>>) 函数并且只传入参数 f 和 g,结果是一个函数,它需要一个单个参数并产生结果 g ( f ( x ) ).
这是一个编写从较小的函数中取出函数:
让否定 x = x * -1让平方 x = x * xlet print x = printfn "数字是:%d" xlet square_negate_then_print = square >>否定 >>打印断言 square_negate_then_print 2
<块引用>
执行时打印‘-4’.
I noticed in some code in this sample that contained the >> operator:
let printTree =
tree >> Seq.iter (Seq.fold (+) "" >> printfn "%s")
What does the >> operator mean/do?
EDIT:
Thanks very much, now it is much clearer. Here's my example I generated to get the hang of it:
open System
open System.IO
let read_lines path = File.ReadAllLines(path) |> Array.to_list
let trim line = (string line).Trim()
let to_upper line = (string line).ToUpper()
let new_list = [ for line in read_lines "myText.txt" -> line |> (trim >> to_upper) ]
printf "%A" new_list
It's the function composition operator.
More info on Chris Smith's blogpost.
Introducing the Function Composition operator (>>):
let inline (>>) f g x = g(f x)
Which reads as: given two functions, f and g, and a value, x, compute the result of f of x and pass that result to g. The interesting thing here is that you can curry the (>>) function and only pass in parameters f and g, the result is a function which takes a single parameter and produces the result g ( f ( x ) ).
Here's a quick example of composing a function out of smaller ones:
let negate x = x * -1
let square x = x * x
let print x = printfn "The number is: %d" x
let square_negate_then_print = square >> negate >> print
asserdo square_negate_then_print 2
When executed prints ‘-4’.
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