Python imaplib 获取正文电子邮件 gmail [英] Python imaplib fetch body emails gmail
问题描述
我已阅读此内容 并编写此脚本以获取某个邮箱中标题以$"开头并由某个发件人发送的电子邮件正文.
I read this already and wrote this script to fetch body for emails in some mail box which title begins with '$' and is sent by some sender.
import email, getpass, imaplib, os
detach_dir = "F:PYTHONPROJECTS" # where you will save attachments
user = raw_input("Enter your GMail username --> ")
pwd = getpass.getpass("Enter your password --> ")
# connect to the gmail imap server
m = imaplib.IMAP4_SSL("imap.gmail.com")
m.login(user, pwd)
m.select("PETROLEUM") # here you a can choose a mail box like INBOX instead
# use m.list() to get all the mailboxes
resp, items = m.search(None, '(FROM "EIA_eLists@eia.gov")')
items = items[0].split() # getting the mails id
my_msg = [] # store relevant msgs here in please
msg_cnt = 0
break_ = False
for emailid in items[::-1]:
resp, data = m.fetch(emailid, "(RFC822)")
if ( break_ ):
break
for response_part in data:
if isinstance(response_part, tuple):
msg = email.message_from_string(response_part[1])
varSubject = msg['subject']
if varSubject[0] == '$':
msg_cnt += 1
my_msg.append(msg)
print msg_cnt
print email.message_from_string(response_part[1])
if ( msg_cnt == 5 ):
break_ = True
如果我打印 email.message_from_string(response_part[1])
,我可以看到它包含第一个信息(标题、发件人、收件人、日期...),全文正文.但是,我无法取回尸体本身.email.message_from_string(response_part[0])
打印邮件 IDS,email.message_from_string(response_part[2])
超出范围.email.message_from_string(response_part[1][0])
两者都没有.
if I print email.message_from_string(response_part[1])
, I can see it contains first information (header, from, to, date...), the the full text body. But, I cannot fetch the body itself. email.message_from_string(response_part[0])
prints mails IDS, and email.message_from_string(response_part[2])
is out of range. email.message_from_string(response_part[1][0])
neither is doing it.
谢谢和问候.
更新
现在,我几乎可以拥有正文了.然而,它仍然被首先出现的信息声明破坏了.结果我得到了
Now, I can almost have body text. However, it is still spoilt by an information statement coming first. I get as a result
From nobody Tue Dec 25 11:42:58 2012
US=3D$4.030
EastCst=3D$4.036
NewEng=3D$4.205
CenAtl=3D$4.149
LwrAtl=3D$3.921
Midwst=3D$3.984
GulfCst=3D$3.945
RkyMt=3D$4.195
WCst=3D$4.187
CA=3D$4.268
我想摆脱 From nobody Tue Dec 25 11:42:58 2012
这是信息.我知道我可以解析文本查找第一个相关行...我知道.
and I would like to get rid of From nobody Tue Dec 25 11:42:58 2012
which is information. I know I could parse text look for first relevant line... i know.
实现这一点的代码(插入我的第一个示例)是
The code for achieving so (to plug in my first sample) is
if varSubject[0] == '$':
r, d = m.fetch(emailid, "(UID BODY[TEXT])")
msg_cnt += 1
my_msg.append(msg)
print email.message_from_string(d[0][1])
你有更好的方法吗(没有信息字符串)???更多:现在获取日期的命令是什么?我知道我可以在上面适合的地方做 varDate = msg['date']
,但是如何只获取 day-month-year ?谢谢
Do you have a better way (no info string) ??? More: what is the command to now fetch the date ? I know that I can do varDate = msg['date']
where suited above, but how to just fetch day-month-year ? THANKS
推荐答案
可以通过以下任一方式获取 body 的内容
You can get the contents of the body by doing any of the following
msg.as_string()
str(msg)
repr(msg)
http://docs.python.org/2.7/library/email.message.html#email.message.Message
这篇关于Python imaplib 获取正文电子邮件 gmail的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!