如何使用 grep 匹配空格或换行符 [英] how to use grep to match with either whitespace or newline

问题描述

我想用一个词 grep 一个文件，比如AAA"，它以空格或换行符结尾.我知道如何单独编写它，如下所示，但是在组合它们时遇到问题(从某种意义上说，它同时输出 VVV AAA 和 AAA VVV).

I want to grep a file with a word, say "AAA", and it ends with whitespace or newlines. I know how to write this seperately, as follows, but having problems in combining them (in the sense that it outputs both VVV AAA and AAA VVV).

$echo -e "AAA VVV 
VVV AAA
BBB" | grep "AAA$" 
>VVV AAA
$echo -e "AAA VVV 
VVV AAA
BBB" | grep "AAA[[:space:]]" 
>AAA VVV 

我曾尝试使用 []，但没有成功..

I have tried using [], but without success..

推荐答案

如果您要查找单词 AAA 后跟空格的字符串中任意位置或行尾，请使用

If you are looking for word AAA followed by space anywhere in the string, or at the end of line, then use

grep -P "AAA( |$)"

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