jackson 将 json 反序列化为 java-objects [英] jackson deserialization json to java-objects
问题描述
这是我用于反序列化的 Java 代码,我正在尝试将 json 字符串转换为 java 对象.为此,我使用了以下代码:
Here is my Java code which is used for the de-serialization, i am trying to convert json string into java object. In doing so i have used the following code:
package ex1jackson;
import com.fasterxml.jackson.core.JsonGenerationException;
import com.fasterxml.jackson.databind.JsonMappingException;
import com.fasterxml.jackson.databind.ObjectMapper;
import java.io.IOException;
public class Ex1jackson {
public static void main(String[] args) {
ObjectMapper mapper = new ObjectMapper();
try {
String userDataJSON = "[{"id":"value11","name": "value12","qty":"value13"},"
+ "{"id": "value21","name":"value22","qty": "value23"}]";
product userFromJSON = mapper.readValue(userDataJSON, product.class);
System.out.println(userFromJSON);
} catch (JsonGenerationException e) {
System.out.println(e);
} catch (JsonMappingException e) {
System.out.println(e);
} catch (IOException e) {
System.out.println(e);
}
}
}
和我的 product.java 类
and my product.java class
package ex1jackson;
public class product
{
private String id;
private String name;
private String qty;
@Override
public String toString() {
return "Product [id=" + id+ ", name= " + name+",qty="+qty+"]";
}
}
我收到以下错误.
com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException:
Unrecognized field "id" (class ex1jackson.product), not marked as ignorable (0 known properties: ]) at
[Source: java.io.StringReader@16f76a8; line: 1, column: 8] (through reference chain: ex1jackson.product["id"])
BUILD SUCCESSFUL (total time: 0 seconds)
帮我解决这个问题
推荐答案
看起来您正在尝试从实际描述数组的 JSON 中读取对象.Java 对象被映射到带有花括号 {}
的 JSON 对象,但你的 JSON 实际上以方括号 []
开始,指定一个数组.
It looks like you are trying to read an object from JSON that actually describes an array. Java objects are mapped to JSON objects with curly braces {}
but your JSON actually starts with square brackets []
designating an array.
你实际上拥有的是一个List
为了描述泛型类型,由于Java 的类型擦除,你必须使用一个TypeReference
.您的反序列化可以是: myProduct = objectMapper.readValue(productJson, new TypeReference
>() {});
What you actually have is a List<product>
To describe generic types, due to Java's type erasure, you must use a TypeReference
. Your deserialization could read: myProduct = objectMapper.readValue(productJson, new TypeReference<List<product>>() {});
另外几个注意事项:您的类应该始终是 PascalCased.您的 main 方法可以是 public static void main(String[] args) throws Exception
,它可以为您节省所有无用的 catch
块.
A couple of other notes: your classes should always be PascalCased. Your main method can just be public static void main(String[] args) throws Exception
which saves you all the useless catch
blocks.
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